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Oksi-84 [34.3K]
3 years ago
15

What type of friction is using chalk in the summer to draw on the ground in Copley square?

Physics
1 answer:
Lera25 [3.4K]3 years ago
7 0
The second option rolling friction
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Tasha has mass 20 kg and wants to use a 4.0-m board of mass 10 kg as a seesaw. her friends are busy, so tasha seesaws by herself
ELEN [110]
The 4 m board's center of mass is 2 m so the pivot point is somewhere between Tasha and 2 m (if you draw a picture it's going to make this clearer)

 The mass of Tasha * her distance from the pivot point = the board's mass * distance from the pivot point. 
<span> Let d1 be the distance Tasha is from the pivot point. The board's center of mass from the pivot point is 2 m - d1 
</span><span> 20 kg * d1 = 10 kg * (2m - d1) 
</span><span> Solve for d1, you should get 2/3 of a m for the distance Tasha is from the pivot or support point. The center of mass for the board is 1 1/3 m from the support point. </span>
8 0
3 years ago
What types of substances tend to be acidic
Fynjy0 [20]
Generally speaking, there are two types of substances; acids and bases. Bases tend to be alkaline and have a higher Ph while acids are acidic and have a lower value on the Ph scale. 
3 0
3 years ago
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What happens when a star's core runs out of hydrogen and why does this occur?
Ad libitum [116K]
When the core runs out of hydrogen to fuse, then it starts fusing the helium. This happens because a star cannot create more hydrogen.
5 0
4 years ago
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While standing at the top of an 100 m high observatory, you accidentally dropped your phone through the grates (it is now fallin
Arturiano [62]

Using the idea of motion under gravity, it will take 0.5 seconds more before the phone hits the ground.

<h3>What is the distance covered?</h3>

The distance covered is obtained form the equations of kinematics under gravity.

Now;

v = u + gt

Recall that it was dropped from a height hence u = 0 m/s

v = gt

v = 9.8 m/s^2 * 4 s

v = 39.2 m/s

Now;

h = ut + 1/2gt^2

but u = 0 m/s

h = 1/2gt^2

h = 1/2 * 9.8 * (4)^2

h = 78.4 m

The phone  will not hit the ground within this time

For the phone to hit the ground;

h = 1/2gt^2

if h = 100 m

100 = 1/2 * 9.8 * t^2

2 * 100/9.8 =  t^2

t = √2 * 100/9.8

t = 4.5 seconds

It will take about 0.5 seconds more before the phone will hit the ground.

Learn more about motion under gravity:brainly.com/question/15120445

#SPJ1

3 0
2 years ago
If |v|= 11, |w|= 23, |v-w|= 30, find |v+w|​
GenaCL600 [577]

Answer:

|v+w|=20

Explanation:

We are given that

|v|=11

|w|=23

|v-w|=30

We have to find the value of |v+w|

|a-b|^2=(a+b)\cdot (a+b)=a^2+b^2-2|a||b|cos\theta

Using the formula

(30)^2=(11)^2+(23)^2-2(11)(23)cos\theta

900=121+529-506cos\theta

900-121-529=-506cos\theta

250=-506cos\theta

cos\theta=-\frac{250}{506}

|a+b|^2=|a|^2+|b|^2+2a\cdot bcos\theta

Using the formula

|v+w|^2=(11)^2+(23)^2+2(11)(23)\times (-\frac{250}{506})

|v+w|^2=400

|v+w|^2=(20)^2

|v+w|=20

7 0
3 years ago
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