Answer:
L= 3.6mH
C =9.9 microfarad
Explanation:
Resonant frequency fr
fr = fl + 1/2 BW
fr = 800+ 1/2×80
=800+40
=840 rad/s
Bandwidth (BW)
BW = fr/Q
Q = quality factor
Q= fr/ BW
Q = 840/80
Q= 10.5
Quality factor = R/Xl
Xl = inductive reactance
Xl = R/Q
Xl = 200/10.5
Xl = 19.05 ohms
Xl =2πfL
L= Inductance
L = Xl /2πf
L =19.05/5278.56
Capacitor C
1= fr^2 × 4π^2LC
C = 1/fr^24π^2L
C = 1/100307.5
C= 9.9microfarad
i d k
D. a concave mirror
To solve this problem, we use the equation:
<span>d = (v^2 - v0^2) / 2a</span>
where,
d = distance of collapse
v0 = initial velocity = 101 km / h = 28.06 m / s
v = final velocity = 0
a = acceleration = - 300 m / s^2
d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)
<span>d = 1.31 m</span>
