Yes the answer would be B
no solution, since the graph two parallel lines with no intersect
Answer:ez just divise all
Step-by-step explanation:
Answer:
Step-by-step explanation:
The attached photo shows the diagram of quadrilateral QRST with more illustrations.
Line RT divides the quadrilateral into 2 congruent triangles QRT and SRT. The sum of the angles in each triangle is 180 degrees(98 + 50 + 32)
The area of the quadrilateral = 2 × area of triangle QRT = 2 × area of triangle SRT
Using sine rule,
q/SinQ = t/SinT = r/SinR
24/sin98 = QT/sin50
QT = r = sin50 × 24.24 = 18.57
Also
24/sin98 = QR/sin32
QR = t = sin32 × 24.24 = 12.84
Let us find area of triangle QRT
Area of a triangle
= 1/2 abSinC = 1/2 rtSinQ
Area of triangle QRT
= 1/2 × 18.57 × 12.84Sin98
= 118.06
Therefore, area of quadrilateral QRST = 2 × 118.06 = 236.12
Answer with Step-by-step explanation:
16 19 21 26 27 29 34 35 35 39 40 41 42 50 50 52 57 60 75 76 78 81 84
the data is already arranged in ascending order
Min=16
Max=84
The quartiles for the odd set of data is given by
![Qi=\dfrac{i(n+1)}{4}\ th\ term](https://tex.z-dn.net/?f=Qi%3D%5Cdfrac%7Bi%28n%2B1%29%7D%7B4%7D%5C%20th%5C%20term)
where n is the number of elements
Here, n=23
![Q1=\dfrac{(23+1)}{4}\ th\ term](https://tex.z-dn.net/?f=Q1%3D%5Cdfrac%7B%2823%2B1%29%7D%7B4%7D%5C%20th%5C%20term)
Q1=6 th term
Q1=29
Q2=12 th term
Q2=41
Q3=18 th term
Q3=60
Hence, five-number summary for the given data is:
Min Q1 Q2 Q3 Max
16 29 41 60 84