A cylinder has a radius of 7 inches and a height of 20 inches. Which is closest to the surface area

2 answers:

3 0

$\bf \stackrel{\textit{surface area of a right-circular cylinder}}{SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=7\\ h=20 \end{cases}}\implies SA=2\pi (7)(20+7) \\\\\\ SA=14\pi (27)\implies SA=378\pi \implies \boxed{SA\approx 1187.52}$

which one is closest from that list? well, pretty sure you already know.

belka [17]2 years ago

3 0

The surface area of a cylinder with a height of 20 in and a 7 in radius is 1,187.52 which is closest to C) 1,187 sq in

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Two sides of an acute triangle measure 5 inches and 8 inches. The length of the longest side is unknown.

nordsb [41]

The greatest whole possible whole number length of the unknown side is 9 inches

Solution:

Two sides of an acute triangle measure 5 inches and 8 inches

The length of the longest side is unknown

We have to find the length of unknown side

The longest side of any triangle is a hypotenuse

For a acute triangle we know:

If c is the longest side of a acute triangle, a and b are other two sides of a acute triangle then the condition that relates these three sides are given as:

$c^2$