A. When you equalize two equations, geometrically you are trying to find the intersection point of them, i.e. find the common point of them. So the x coordinate of the intersection point is basically the solution.
B. You can simply plug in numbers from -3 to 3 and list the values by yourself.
C. Graphically, draw each equation, and find the x coordinate of the intersection point.
FYI, the solution is x = 1/3
Answer:
Use the Pythagorean Theorem to find the diagonal:
Answer
Step-by-step explanation:
Answer:
d.2/6 has a repeating decimal form
Answer:
L=21.6in and w=13.6
Step-by-step explanation:
If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8
Area is (width)(Length) = (width)(width+8)
W
----------
| |
| |
| | L = w+8
| |
| |
-----------
A = (w+8)(w)
A = w2 + 8w = 295.
(Problem states that area is 295 sq in)
Need to solve this quadratic equation
w2 +8y - 295 = 0
Factor:
(w - 13.64) (w + 21.64) = 0
So
w - 13.64 = 0. or. w + 21.64= 0
Solve these and get
w = 13.64. or. w = -21.64
Only one that makes sense in real life is the poitive one.
So the dimensions are
Width = 13.64 inches
Length = 21.64 inches
