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Mice21 [21]
3 years ago
8

A man invests $2000 in an account that pays 8.5% interest per year, compounded quarterly. (a) find the amount after 2 years? (ro

und your answer to the nearest cent.)
Mathematics
1 answer:
Inessa [10]3 years ago
4 0

A man invests $2000 into an account that accrues 8.5% interest compounded quarterly. He made the deposit of 2 years , i.e. for 8 quarters ( or 8 compounding periods)

Amount after n years is calculated by following equation :

Amount = Principal * ( 1 + Interest rate per compounding period ) ^ no. of compounding periods

The amount in his account after 2 years = 2000 * ( 1 + 0.085/4) ^ 8

= 2000 * (1.02125 ) ^ 8

= 2000 * 1.18319

= $2366.39

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Simplify the algebraic expression:<br><br> 2(y + 5) + 3y - 4
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Answer:

2y +10 +3y-4

5y+6

Step-by-step explanation:

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There are 100m of ribbon. 1 1/2m are needed to make a bouquet. How man can be made? How many m of ribbon are left over ?
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Answer:

66 can be made

1m left

Step-by-step explanation:

100 \div 1.5 = 66.667(5s.f.)

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8 0
3 years ago
June 1st = 1223 starting balance
Dima020 [189]

<u>Answer:</u>

The average daily balance for the month of June is 55.16

Solution:

Given, June 1st = 1223 starting balance

June 10th = 615 deposit

So these will add in the account

June 15th = withdrawal of -63

June 22nd = withdrawal of -120

These will be subtracted from the account.

\therefore We have to add the deposits and subtract the withdrawals from the starting balance to obtain the total amount.

So, the total amount deposited in June is (1223 +615-63-120) = 1655

The total days in June is 30. In 30 days, the total deposit is 1655. To calculate the average balance, we have to divide the total amount by the total number of days in the month.

So, in 1 day the deposit is \frac{1655}{30} = 55.16

Hence, the average daily balance for June is = 55.16  

5 0
3 years ago
How could you write this number in standard from 8.234 E14 PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELP
marissa [1.9K]

Answer:

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Step-by-step explanation:

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Evaluate exactly without the use of a calculator (remember to rationalize any denominators). a.(cos 60o)(sin 270o) + tan 225o b.
Rom4ik [11]

Given:

The trigonometric expressions are given as,

\begin{gathered} a)\text{ }(\cos 60\degree)(\sin 270\degree)+\tan 225\degree \\ b)-\tan 240\degree+(cos45\degree)(\sec 135\degree) \end{gathered}

Explanation:

a)

The given expression can be rewritten as,

=(\cos 60\degree)(\sin (360\degree-90\degree))+\tan (270\degree-45\degree)\text{ . . . .  .(1)}

Since, from the trigonometric ratios,

\begin{gathered} \sin (360\degree-90\degree)=-\sin 90\degree \\ \tan (270\degree-45\degree)=\cot 45\degree \end{gathered}

On plugging the obtained ratios in equation (1),

=(\cos 60\degree)(-\sin 90\degree)+\cot 45

Substitute the trigonometric values in the above equation.

\begin{gathered} =\frac{1}{2}(-1)+1 \\ =-\frac{1}{2}+1 \\ =\frac{1}{2} \end{gathered}

Hence, the exact value of the expression is 1/2.

b)

The given expression can be rewritten as,

=-\tan (270\degree-30\degree)+(\cos 45\degree)(\sec (90\degree+45\degree))\text{ . . . ..(2)}

Since, from the trigonometric ratios,

\begin{gathered} \tan (270\degree-30\degree)=\cot 30\degree \\ \sec (90\degree+45\degree)=-\csc 45\degree \end{gathered}

On plugging the obtained ratios in equation (2),

=-\cot 30\degree+(\cos 45\degree)(-\csc 45)

Substitute the trigonometric values in the above equation.

\begin{gathered} =-\sqrt[]{3}+\frac{1}{\sqrt[]{2}}(-\sqrt[]{2}) \\ =-\sqrt[]{3}-1 \end{gathered}

Hence, the exact value of the expression is -√3-1.

7 0
1 year ago
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