Question

Please help condense into a single logarithm:

Answer 1

The first step for solving this expression is to write the number below ㏒ in exponential form.
㏒$_{ 3^{2} }$(x) + 2㏒$_{ 3^{2} }$(y) - ㏒$_{2}$(z)
Using ㏒$_{a^{y} }$(b) = $\frac{1}{y}$ × ㏒$_{a}$(b),, transform the expressions with ㏒$_{ 3^{2} }$.
$\frac{1}{2}$ × ㏒$_{3}$(x) + $\frac{1}{2}$ × ㏒$_{3}$(y) - ㏒$_{2}$(z)
Lastly,, reduce the numbers with 2 to find your final answer.
$\frac{1}{2}$ × ㏒$_{3}$(x) + ㏒$_{3}$(y) -  ㏒$_{2}$(z)
This means that the correct answer to your question is $\frac{1}{2}$ × ㏒$_{3}$(x) + ㏒$_{3}$(y) -  ㏒$_{2}$(z).
Let me know if you have any further questions.
:)