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3 years ago

How many solutions does the system have?

Mathematics

1 answer:

Anit [1.1K]3 years ago

3 0

The answer is C because they intercept with each other as they have the same equation as for slope and y intercept

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F(t)=t^2-3t g(t)=2t+1 find f(g(t))

statuscvo [17]

Answer:

$f (2t + 1) = 4t^{2} - 2t - 2$

7 0

2 years ago

Write two equivalent fractions for each. 1/2 and 4/5

Butoxors [25]

An equivalent fraction for 1/2 would be 2/4. This is because you can simplify 2/4 by dividing it by 2. The final answer would be 1/2.

An equivalent fraction for 4/5 would be 8/10. It's basically the same thing. Divide them both by 2 and you'll get 4/5 since 8 divided by 2 is 4, and 10 divided by 2 is 5.

5 0

3 years ago

Simplify the following expression. 0.82 / 0.2

AlekseyPX

Answer:

0.41

Step-by-step explanation:

0.82 = 0.2 x 0.41

0.82 / 0.2

= ( 0.2 x 0.41 ) / 0.2

= 0.41

5 0

3 years ago

Read 2 more answers

Consider the expression 6n2 + 2n + 3 . What is the coefficient of n?

ad-work [718]

Answer:

Step-by-step explanation:

The coefficient is the number in front of the variable.

So, in this case, the coefficient of n^2 is 6 and of n is 2.

6 0

3 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

3 years ago