Answer:
0.000003721m
Scientific Notation: 3.72*10^-6
Step-by-step explanation:
1nm is 1*10^-6nm
Based on that we find the answer above.
<h2><u>
Answer with explanation</u>
:</h2>
Let
be the population mean.
As per given , we have

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given
, so we perform one-tailed z-test.
Test statistic : 
, where
= Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 ,
,
,
, we have

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
Hello there!
So, as we see here, we can see that they start out with 20,000 members. 25% of 20,000 would be 5,000 members.
So, every year, they lose 25% which is 5,000 members of they team. But then they gain 10,000 more.
So, practically, they get 5,000 every year even though they get 25% off.
5,000 would be the answer.
When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5
<span>= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 </span>
<span>= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 </span>
<span>= x^3 - x^2 - 4x - 1
</span>I hope this helps