3 years ago

Which is a possible turning point for the continuous function f(x)? HELP ASAP

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

Step-by-step explanation:

maxonik [38]3 years ago

7 0

Answer: B. (-2, -1)

Step-by-step explanation:

(-2, -1) has a y-coordinate (-1) closer to 0 than the rest of the y-coordinates. And 0 would be turning point in this equation.

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3 years ago

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maxonik [38]

Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

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2 years ago

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s344n2d4d5 [400]

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Step-by-step explanation:

The given equation of the circle is:

$x^{2} + y^{2}+8x-6y+21=0$

The general equation of the circle is:

$x^{2} + y^{2}+2gx+2fy+c=0$

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

$radius=\sqrt{g^{2} +f^{2} -c }$

Using these values of the given circle, we get:

$radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2$

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