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frez [133]
3 years ago
9

What are the physics terms behind watching TV?

Physics
1 answer:
GalinKa [24]3 years ago
3 0
Everyone knows that one of their favorite past times is sitting in front of the television and watching movies, shows, or playing video games. However with this almost motionless, lazy activity comes a great deal of static physics and mechanics.

When you are sitting down enjoying whatever show it is you may be watching, you actually have several forces acting on you concurrently. For example, by sitting on the couch with no extra weight on you, your weight is equivalent to the normal force, or the force of the couch on you. In addition to the force of the couch of you, if you are leaning on an arm or laying down, a similar force acts on you, except at an angle or incline. The general rule for laying on the couch watching television is that whatever force you exert on an object, that object exerts the same force in the opposite direction, or 180 degrees around.

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What is the current in mA through a 500 Ω resistor that is connected to a 1.5 V battery? Show all calculations using Ohm’s law (
Ludmilka [50]

Answer:

3 mA.

Explanation:

The following data were obtained from the question:

Resistor (R) = 500 Ω

Potential difference (V) = 1.5 V

Current (I) =.?

Using the ohm's law equation, we can obtain the current as follow:

V = IR

1.5 = I x 500

Divide both side by 500

I = 1.5 / 500

I = 3×10¯³ A.

Therefore, the current in the circuit is 3×10¯³ A.

Finally, we shall convert 3×10¯³ A to milliampere (mA).

This can be obtained as follow:

Recall:

1 A = 1000 mA

Therefore,

3×10¯³ A = 3×10¯³ × 1000 = 3 mA

Therefore, 3×10¯³ A is equivalent to 3 mA.

Thus, the current in mA flowing through the circuit is 3 mA.

3 0
3 years ago
F a forklift raises a 76-kg load a distance of 2.5 m, about how much work has it done?
sleet_krkn [62]

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A stone is tied to a string and whirled at constant speed in a horizontal circle. The speed is then doubled without changing the
Tanya [424]

Answer:

Afterward the magnitude of the acceleration of the stone is four times as great

Explanation:

A stone tied to a string and whirled at a constant speed in a horizontal circle will have a centripetal acceleration given by

a = \frac{v^{2} }{r}

Where a is the centripetal acceleration

v is the speed

and r is the radius of the circle

Here, the radius of the circle is the length of the string.

Now, from the question

The speed is then doubled without changing the length of the string,

Let the new speed be v_{2}, that is

v_{2} = 2v

and without changing the length of the string means radius r is constant.

To determine the magnitude of the acceleration of the stone afterwards,

Let the new acceleration be a_{2}.

Then we can write that

a_{2} = \frac{v_{2}^{2}  }{r}

From

a = \frac{v^{2} }{r}

v = \sqrt{ar}

Recall that

v_{2} = 2v

∴ v_{2} = 2\sqrt{ar}

Now, we will put the value of v_{2} into

a_{2} = \frac{v_{2}^{2}  }{r}

Then,

a_{2} = \frac{(2\sqrt{ar}) ^{2}  }{r}

a_{2} = \frac{4ar }{r}

a_{2} = 4a

The new magnitude of the acceleration of the stone is four times the initial acceleration.

Hence,

Afterward the magnitude of the acceleration of the stone is four times as great

3 0
3 years ago
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