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Rudik [331]
4 years ago
6

Three identical springs each have the same spring constant k. if these three springs are attached end to end forming a spring th

ree times the length of one of the original springs, what will be the spring constant of the combination?
Physics
1 answer:
wlad13 [49]4 years ago
6 0
If the springs are connected together from end to end, they are arranged in series. For springs in series, the forces are additive. 

Spring 1: F1 = k1(Δx1)
Spring 2: F2 = k2(Δx2)
Spring 1: F3 = k3(Δx3)

Total Force = k1(Δx1)+k2(Δx2)+k3(Δx3)
Total Force = (k1+k2+k3)(Δx,total)

The spring constants are added together and multiplied with the total length of elongation to find the total force acting on it.
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Andre45 [30]

You see its position before and then its position after.

6 0
3 years ago
2) The position of a particle is given r(t) = A(cos wt i + sin wt f), where w is a constant. (a) Show that the particle moves in
olya-2409 [2.1K]

Answer:

Explanation:

r(t) = A(cos wt i + sin wt f)

= A cos wt i + A sin wt j

x = A cos wt

y = A sin wt

radius r

r² = x² + y² ( This is equation of a circle with radius r  )

=  A² cos² wt +A² sin² wt

= A²

r = A

radius r = A

b )

speed = dr/dt

v = - Aw sinwt i + Aw coswt j

magnitude of velocity

I v I= Aw √(sin²wt + cos²wt)

= Aw ( constant )

acceleration

= dv / dt = - Aw² cos wt - Aw² sinwt

magnitude of acceleration

I a I = Aw²

= r w²

d ) centripetal force = m acceleration

m w² A  

=

7 0
3 years ago
The heating of the lower layer of the atmosphere from radiation absorbed by certain heat- absorbing gasses is called ?
abruzzese [7]
I think you're talking about the 'greenhouse effect'.
8 0
3 years ago
A car undergoing uniform acceleration travels 100 meters from a standing start in a given period of time. If the time were incre
iogann1982 [59]

Answer:

d = 1600 m

Explanation:

If car start from rest and accelerates uniformly then the displacement of the car is given as

d = v_i t + \frac{1}{2}at^2

now we know

d = 0 + \frac{1}{2}at^2

now if the same car will accelerate from rest for four times of the previous time interval

then we will have

d = 0 + \frac{1}{2}a(4t)^2

d = 16(\frac{1}{2}at^2)

so the distance will be 16 times more

d = 1600 m

5 0
4 years ago
a gust of wind blows an apple from a tree. As the apple falls, the gravitational force on the apple is 2.25N downward and the fo
IRISSAK [1]

Vertical component =  2.25 N downward

Horizontal component = 1.05 N to the right

Magnitude of the net force = √ (2.25² + 1.05²)
                                              = √6.165 =              2.483 N  (rounded)

Direction of the net force = tan⁻¹ (1.05/2.25) to the right of downward

                                           = tan⁻¹ ( 7/15 ) to the right of downward

                                           = 25° to the right of downward (rounded)
5 0
4 years ago
Read 2 more answers
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