Im sure this answers your question greatly
Answer:
Discriminant: -4
No real solutions
Step-by-step explanation:
You might remember this long, seemingly very hairy thing called the <em>quadratic formula</em> from earlier in algebra:
The <em>discriminant</em> of a quadratic equation of the form is that bit under the square root: . What does the discriminant tell us? Since we're taking its square root, we know that is only real for non-negative values of . If , we have two real roots, one for and one for . If , the function has a rational root, since the formula becomes
In your case, we have the equation ; here, , , and , so our discriminant is . Since we'd have a negative under our square root in the quadratic formula, we have <em>no real solutions</em>.
Answer:
- x = 31 - 2y - 3z
- y = (31 - x - 3z)/2
- z = (31 -x -2y)/3
Step-by-step explanation:
Subtract the terms not containing the variable of interest, then divide by the coefficient of the variable.
x = 31 -2y -3z . . . . . the coefficient of x is 1, so we're done
__
2y = 31 -x -3z
y = (31 -x -3z)/2
__
3z = 31 -x -2y
z = (31 -x -2y)/3
Answer: 41 inches by 6 inches
Step-by-step explanation:
A poster is in form of a rectangle and the area is length × breadth.
If the area of the poster is 240in² with 1 inch margins at the bottom and sides and 2in margin at the top.
The extra length of the poster will be 1-in at the bottom plus 2-in margin at the top making additional height of 3-inches.
Also, the extra breadth the 1-in at the sides to give breadth of extra 2-inches in total.
The area of the extra length and breath will be 3inches × 2inches to give 6inches.
The area that will give the exact dimension will be 240inches+6inches = 246inches
The dimension an be 41inches by 6inches
Answer:
The dimension of the cardboard is 34 cm by 34 cm by 17 cm.
Step-by-step explanation:
Let the dimension of the cardboard box be x cm by y cm by z cm.
The surface area of the cardboard box without lid is
f(x,y,z)= xy+2xz+2yz.....(1)
Given that the volume of the cardboard is 19,652 cm³.
Therefore xyz =19,652
......(2)
putting the value of z in the equation (1)
The partial derivatives are
To find the dimension of the box set the partial derivatives and .Therefore
.......(3)
and
.......(4)
Now putting the x in equation (3)
⇒y=34 cm
Then =34 cm.
Putting the value of x and y in the equation (2)
=17 cm.
The dimension of the cardboard is 34 cm by 34 cm by 17 cm.