Answer:
<em>250 cameras / day</em>
<em>The daily profit would be $300</em>
Step-by-step explanation:
<u>Modeling With Equations</u>
Some situations in real life are adequate for being modeled as functions of the variables they depend on. Equations can be of great help for economy calculations since we could determine optimum levels of production, revenue, costs, and other useful information.
The fixed cost our camera manufacturer is $1500 each day and a variable cost of $9 per camera sold. It can be written as
C(x)=1500+9x
Being C(x) the total cost of manufacturing, and x the number of cameras sold each day
If the company sells the cameras for $15 apiece, then the revenue for x cameras will be
R(x)=15x
a)
We want to find out how many cameras must be sold to equal its daily cost, so
1500+9x=15x
6x=1500
x=250 cameras / day
b) Given the manufacturer can increase production by 50 cameras per day (x=300), then the revenue will be
R(300)=15(300)=$4500
And the cost
C(300)=1500+9(300)=4200
The daily profit would be $4500-$4200=$300
