Let be an exponential function of the form $y = A\cdot e^{B\cdot x}$ , where $A$ and $B$ are real numbers. A horizontal asymptote exists when $e^{B\cdot x} \to 0$ , which occurs for $B\cdot x \to - \infty$ .

For this function, the horizontal asymptote is represented by $y = 0$ and to change the value of the asymptote we must add the parent function by another real number ( $C$ ), that is to say:

$y = A\cdot e^{B\cdot x} + C$ (1)

In this case, we must use $C = -3$ to obtain an horizontal asymptote of -3. Thus, the right choice is: A whole number constant could have been subtracted from the exponential expression.

To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280

3 0

2 years ago

Read 2 more answers

At Pizza Pi, 32% of the pizzas made last week had extra cheese. If 16 pizzas had extra cheese, how many pizzas in all were made

igor_vitrenko [27]

Answer:

Step-by-step explanation:

you need to put first the 32 on top of 100 since it always goes over 100 then you put 16 over a blank and you divide 32 by 16 which equals 2 so since you divided at the top you need to divide at the bottom so you divide 100 by 2 and you get 50 so 50 is your answer

7 0

3 years ago