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vredina [299]
4 years ago
10

In order to measure current in a circuit, the multi-meter needs to be placed in __A__ , while when measuring voltage, the multi-

meter needs to be placed in __B__ with the circuit. Group of answer choices A - Series, B - Parallel A - Series, B - Series A - Parallel, B - Series A - Parallel, B - Parallel
Physics
1 answer:
lakkis [162]4 years ago
3 0

Answer:

A- series B- parallel

Explanation:

In order to measure current in a circuit, the multi-meter needs to be placed in series with the circuit while when measuring voltage, the multi-meter needs to be placed in parallel with the circuit.

It should be however noted that the same current flows in a series connected circuit and same voltage flows through loads connected in parallel. The ammeter is placed in series with the load to ensure that same value of currents is flowing in both the ammeter and loads(since same current flows in series connected circuit elements and all the amount of voltage must be made to appear on the load for the current to be measured accurately.

Voltmeter is connected in parallel to the load due to high value of current possessed by the voltmeter. The parallel connection will cause the current flowing through the voltmeter to reduce to zero so that it won't have effect (increase) on the amount of current initially on the resistor thereby measuring the exact amount of voltage on the load.

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Pls help with science!!!!!​
Andrews [41]

Answer:

Your answer is C~

Explanation:

4 0
3 years ago
A converging lens brings rays of light together at a focal point. The bending of light rays is the result ofA. A combination of
Tcecarenko [31]

Answer:

.C. Refraction of light passing through the lens.

Explanation:

The convergence or divergence of the rays of light is only due to refraction of light.  When a ray of light is made to pass through a lens, it bend's from it's original path. This bending of light from its original path is called Refraction. Whereas in Reflection the ray of light is reflected back into the same medium.

Hence the correct option is C. Refraction of light passing through the lens.

5 0
3 years ago
Bill leaves his 60 W desk lamp on every day, including weekends, for eight hours. After one month (30 days), how much total ener
PolarNik [594]
First multiply the 30 days by 8 hours to get 240, then take that number and multiply it by 60 W to get the final  answer of 14400. 
hope this is correct, I'm learning it too
8 0
4 years ago
Read 2 more answers
Work done can be describe as?​
Neko [114]

Explanation:

In physics, work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement. A force is said to do positive work if (when applied) it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.

Quick Facts: Common symbols, SI unit ...

Work

A baseball pitcher does positive work on the ball by applying a force to it over the distance it moves while in his grip.

Common symbols

W

SI unit

joule (J)

Other units

Foot-pound, Erg

In SI base units

1 kg⋅m2⋅s−2

Derivations from

other quantities

W = F ⋅ s

W = τ θ

Dimension

M L2 T−2

Close

For example, when a ball is held above the ground and then dropped, the work done by the gravitational force on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). When the force F is constant and the angle between the force and the displacement s is θ, then the work done is given by:

{\displaystyle W=Fs\cos {\theta }}{\displaystyle W=Fs\cos {\theta }}

Work is a scalar quantity, so it has only magnitude and no direction. Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J), the same unit as for energy.

4 0
3 years ago
A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?
ludmilkaskok [199]

The answer is  24.84kJ.

We apply the expression for the work done by the heat engine is,

W=E_{i n}-E_{o u t}. Putting all given values in the equation we get the final answer.

What is heat engine?

  • A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
  • We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$. The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$.
  • The expression for the work done by the heat engine is,W=E_{i n}-E_{o u t}
  • Substituting the given values in the above expression, we will getW =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}=24.84kJ.
  • Thus, the work done by the heat engine is 24.84kJ.

To learn more about heat engine visit: brainly.com/question/15735984

#SPJ4

6 0
2 years ago
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