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3 years ago

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Which situation shows potential energy transforming into kinetic energy 1.A car stopped at a stoplight 2.A flowerpot falling fro

m a balcony 3.A cow standing in a field 4.A bicycle slowing down

1 answer:

Troyanec [42]3 years ago

7 0

Answer:

2.A flowerpot falling from a balcony

Explanation:

Potential energy is the internal energy within a body at rest or at a height above the ground. In this case of the falling flowerpot, the flowerpot initially has a potential energy due to its position on the balcony above the surface of the earth. As the flowerpot falls, the work done against gravity in taking the flowerpot to this height on the balcony (equivalent to the potential energy) is transformed into the kinetic energy of motion as the flowerpot falls down through the height.

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A 6157 N piano is to be pushed up a(n) 2.41 m frictionless plank that makes an angle of 21.9 ◦ with the horizontal. Calculate th

xz_007 [3.2K]

Answer:

Work done, W = 5534.53 J

Explanation:

It is given that,

Force acting on the piano, F = 6157 N

It is pushed up a distance of 2.41 m friction less plank.

Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :

$W=Fd\ sin\theta$

Since, $F=F\ sin\theta$ (in vertical direction)

$W=6157\times 2.41\ sin(21.9)$

W = 5534.53 J

So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.

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3 years ago

Consider two positively charged particles, one of charge q₀ (particle 0) fixed at the origin, and another of charge q₁ (particle

docker41 [41]

Answer:

Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by

$F=k\frac{q_0q_1}{r^2}$

where r is the distance between the charges & k is the Coulomb's constant

k=1/(4*ε_0*π)

k=9*10^9

the distance between the charges in this question is d_1

hence the magnitude of the force exerted by q_0 on q_1 is given by

$F=k\frac{q_0q_1}{d_1^2}$

due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form

$F=k\frac{q_0q_1}{d_1^2} j$

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3 years ago

Please help me, I’m confused on where to start.

zimovet [89]

Answer:

D

Explanation:

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2 years ago

Read 2 more answers

Give the number of significant figures: 832.000 km

Galina-37 [17]

It has three significant figure

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3 years ago

You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 77.2 kg hop on board for a ride

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To solve this problem it is necessary to apply the kinematic equations of motion and Hook's law.

By Hook's law we know that force is defined as,

$F= kx$

Where,

k = spring constant

x = Displacement change

PART A) For the case of the spring constant we can use the above equation and clear k so that

$k= \frac{F}{x}$

$k = \frac{mg}{x}$

$k= \frac{77.2*9.8}{0.0637}$

$k = 11876.92N/m$

Therefore the spring constant for each one is 11876.92/2 = 5933.46N/m

PART B) In the case of speed we can obtain it through the period, which is given by

$T = \frac{2\pi}{\omega}$

Re-arrange to find \omega,

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{2.14}$

$\omega = 2.93rad/s$

Then through angular kinematic equations where angular velocity is given as a function of mass and spring constant we have to

$\omega^2 = \frac{k}{m}$

$m = \frac{k}{\omega^2}$

$m = \frac{ 11876.92}{2.93}$

$m = 4093.55Kg$

Therefore the mass of the trailer is 4093.55Kg

PART C) The frequency by definition is inversely to the period therefore

$f = \frac{1}{T}$

$f = \frac{1}{2.14}$

$f = 0.4672 Hz$

Therefore the frequency of the oscillation is 0.4672 Hz

PART D) The time it takes to make the route 10 times would be 10 times the period, that is

$t_T = 10*T$

$t_T = 10 *2.14s$

$t_T = 21.4s$

Therefore the total time it takes for the trailer to bounce up and down 10 times is 21.4s

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3 years ago