Answer:
330 kg for high density liquid
255 kg for low density liquid
Explanation:
Density is defined as mass per unit volume hence expressed as p=m/v where p is density, m is mass and v is volume. Making m the subject of the formula then m=pv
The volume of the given container is given by lwh where l is length, w is width and h is height. Substituting 3m, 0.4 m and 0.5 m for l, w and h then volume is 3*0.4*0.5=0.6 cubic metres
Since the liquids are mixed equally, volume for each is 0.6/2=0.3 cubic metres
Mass of first liquid will be 1100*0.3=330 kgs
Mass for other liquid whose density is 850 kg/m3 will be 0.3*850= 255 Kgs
A 1000J or 1kJ of energy in 1 second implies that in 1 minute there will be 60kJ of energy converted.
Work is the defined as energy consumed thought time.

In our case,

Hope this helps!
Answer:
40J
Explanation:
Kinetic energy = 1/2 mv^2
Where m = mass and
v = velocity
Given mass = 20kg
v = 2m/s
K.E = 1/2 x 20 x2^2
= 1/2 x 20 x 2 x 2
= 80/2
= 40J
Answer:
30 seconds
Explanation:
The formula for calculating acceleration is
( final velocity - inital velocity) ÷ time
If we enter the values, it would be (250 - 100) ÷ t = 5m/s^2
Now we need to know 't'
So we rearrange the equation to make t the subject.
(250-100) ÷ 5 = 30s
Answer:
α = F/(k×m×r)
Explanation:
When the wheel is pulled to turn in a counterclockwise direction, the wheel will have a moment of inertia given by Iw = k×m×r²
Where k = the radius of gyration of the wheel which is a dimensionless quantity less than one.
m = the mass of the wheel
r = the radius of the wheel
First and foremost, we relate the torque (τ) about the axle of the wheel to the force (F) applied on the wheel and we have that τ = r × F
We then relate the torque on the wheel to the angular acceleration (α), we have that τ = Iw × α, where Iw is the moment of inertia of the wheel as explained above
Substituting for torque τ and moment of inertia I into the above equation we have that
r × F = k×m×r² × α
solving for α we have that
α = r × F /(k×m×r²)
Therefore
α = F/(k×m×r)