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Karolina [17]
3 years ago
9

Dogs are able to hear much higher frequencies than humans are capable of detecting. For this reason, dog whistles that are inaud

ible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 30000 Hz, what is the wavelength of the sound emitted? 
Physics
1 answer:
stellarik [79]3 years ago
4 0
Wavelength = 1/frequency thus wavelength =1/30000
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How much water can be held by a cylindrical tank with a radius of 12 feet and a height of 30 feet? A. 2,260.8 cubic feet B. 13,5
MakcuM [25]

Answer:

Volume, V = 13564.8  cubic feet

Explanation:

It is given that,

Radius of the cylindrical tank, r = 12 feet

Height of the tank, h = 30 feet

We need to find the water that can be held by a cylindrical tank i.e. we need to find the volume of the tank. It is given by :

V=\pi\times r^2\times h

V=3.14\times (12)^2\times 30

V = 13564.8  cubic feet

So, the water held by the tank is 13564.8  cubic feet. Hence, this is the required solution.

6 0
3 years ago
Looking that following diagram of bar magnets, determine if the magnets will or will not connect (attract) and why.
vovangra [49]

Answer: They will NOT connect because like poles are facing each other, and like poles repel each other.

3 0
4 years ago
Compare and contrast carbon to its isotopes: what is different about them and what is the same?
Alex_Xolod [135]
Their atomic numbers are all the same, because they all have the same number of protons. But their atomic weights are different, because they have different numbers of neutrons.
6 0
4 years ago
A rock falls from a tower that is 320 feet high. As it is​ falling, its height is given by the formula h equals 320 minus 16 t s
RSB [31]

Answer:

a. 4.5secs

Explanation:

From the question, the equation describing the height is given by

h(t)=320-16t^{2}\\

at the point when the rock hit the ground, the height,h will be zero.

Hence we can have

h(t)=320-16t^{2}\\\\at  h(t)=0\\0=320-16t^{2}\\hence \\320=16t^{2}\\t^{2}=\frac{320}{16}\\ t^{2}=20\\t=\sqrt{20}\\ t=4.47secs\\t=4.5sec\\

hence the rock will hit the ground in 4.5secs

4 0
4 years ago
Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same
alekssr [168]

Answer:

<em>Good Luck!</em>

Explanation:

Force applied by first student (F1) = 80 N

Force applied by the second student (F2) = 40 N

Displacement (d) = 10 m

Work done by first student (W1) = F1d = 80*10 = 800 J

Work done by second student (W2) = F2d = 40*10 = 400 J

Hence, the work done by the pushing student is 800 J and that by pulling student is

<h2> <u><em>400 J</em></u></h2>
5 0
3 years ago
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