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3 years ago

What are the next five terms

Mathematics

1 answer:

slega [8]3 years ago

5 0

Good luck dude... if i knew though i would tell you how.

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For which pairs of functions is (f * g) (x)?

Ronch [10]

Answer:

The pairs of functions that best represent the equation are f(x)=x² and g(x)=1/x

Step-by-step explanation:

For this problem, you will have to multiply each equation in the answer choices until you find the pair that has a product of x.

Let's start with the first answer choice.

(f * g)(x)

Now, we multiply these terms together.

x² * 1/x = x²/x

Now, divide x from x². When you are dividing exponents, the exponential numbers subtract. So, since there is no exponent on x, then we assume this exponent to be 1. So, when dividing you will subtract 1 from 2.

x²/x = x

So, the answer to the problem is answer choice A. These functions multiply together to get you a final product of x.

7 0

3 years ago

Lenore is going to sell T-shirts at a field hockeygame to raise money for the team. She findsa website that makes custom T-shirt

sertanlavr [38]

Ndndjdjsjsjsjdjsjsjdnd

5 0

2 years ago

Can you help me please

lions [1.4K]

The answer is -7.137x10^-3

3 0

3 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

3 years ago

Find the area of each figure.

taurus [48]

176ft^2 first
141.3ft^2 second

8 0

3 years ago