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3 years ago

48.7 to one significant figure

Mathematics

2 answers:

madam [21]3 years ago

5 0

48.7 rounded to one significant figure would be 50

pantera1 [17]3 years ago

3 0

48.7 rounded to the closest significant figure would be 50. Hope I helped!

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Evaluate u^2 -2u+4 when u= -3

OLga [1]

Answer:

Step-by-step explanation: Sub -3 into where all the u’s are. So it would be

(-3)^2 - 2(-3) + 4

Which would equal 19

6 0

3 years ago

18. Curry powder is sold at $7.45 per 100 g. How much money will Thuy need in order to buy 3 kg of curry powder?

MissTica

Answer:

Step-by-step explanation:

$7.45 = 100g

x = 3kg( 3 × 1000) = 3000g

∵ $7.45 = 100g

x = 3000g

(100 × x) = (7.45 × 3000)

100x = 22350

100x/100 = 22350/100

x = $223.5

4 0

2 years ago

Read 2 more answers

Arjun solved the equation 7·=56. His work is shown.

alukav5142 [94]

Arjun should have divided both sides of the equation by 7 instead of multiplying.

4 0

3 years ago

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I NEED HELP LIKE RIGHT NOW!!

Bess [88]

Answer:

The answer in the attached figure

Step-by-step explanation:

Let

x------> the abscissa

y-----> the ordinate

we know that

$y=2x$ -----> given problem

The domain is $[-1, 0, 1]$

For $x=-1$

$y=2(-1)=-2$

The point is $(-1,-2)$

For $x=0$

$y=2(0)=0$

The point is $(0,0)$

For $x=1$

$y=2(1)=2$

The point is $(1,2)$

The answer in the attached figure

7 0

3 years ago

Read 2 more answers

Solve this equation. 25) v - 6(4v + 6) = -82

grin007 [14]

Answer:

$v = 2$

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

$v - 6 (4v + 6) = -82$

Distribute:

$v + (-6) (4v) + (-6) (6) = -82$

$v + -24v + -36 = -82$

Combine 'like' terms:

$(v -24v) + (-36) = -82$

$-23v - 36 = -82$

Next, you'll want to add 36 to both sides of the equation.

$-23v-36 + 36 = -82 + 36$

$-23v = -46$

Finally, divide both sides by $-23$ .

$\frac{-23v}{-23} = \frac{-46}{-23}$

$v = 2$

I hope this helped you! Leave a comment below if you have any further questions! :)

7 0

3 years ago