A product is negative when the number of negative numbers in the multiples is odd.
Therefore, options A and C gives negative products.
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Answer:
first one linear
second one quadratic
linear
Step-by-step explanation:
