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Licemer1 [7]
3 years ago
9

A visual basic application consists of a single file true or false

Computers and Technology
2 answers:
Kitty [74]3 years ago
5 0
This would be false visual basic application can consist of more then 1 file
saw5 [17]3 years ago
3 0
False. When decompiled you can see all the files required for it to run
You might be interested in
In python:
egoroff_w [7]

Python can be used to implement central of tendencies such as mean, median and mode using the statistic module

The program in Python, where comments are used to explain each line is as follows:

#This imports the statistics module

import statistics

#This defines the function that calculates the mode

def calcMode(myList):

   #This prints the mode

   print(statistics.multimode(myList))

#This defines the function that calculates the median

def calcMedian(myList):

   #This prints the median

   print(statistics.median(myList))

#The main method begins here

#This initializes the list

myList = []

#The following iteration gets input for the list

for i in range(10):

   myList.append(int(input()))

#This calls the calcMode method

calcMode(myList)

#This calls the calcMedian method

calcMedian(myList)

Read more about similar programs at:

brainly.com/question/25026386

8 0
2 years ago
How fast is light? person that answers this will get points ​
Serhud [2]

299,792,458 metres per second

6 0
3 years ago
Instructions: Use the tables below to answer the questions that follow:
Svet_ta [14]

Answer:

same as above....................

3 0
2 years ago
When using the text command, what needs to be around the word or words you<br> want to appear?
AysviL [449]

Answer:

In most programming languages "" are required around text.

Explanation:

Python: print("text")

HTML: <p>text</p>

C++: int Main() {

cout << "text" << endl;

}

Lua: print("text")

8 0
2 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
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