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morpeh [17]
3 years ago
15

Create and test a user-defined function named ufnFullName that combines the values of the two parameters named FirstName and Las

tName into a concatenated name field FullName, which is formatted as FirstName LastName (including a space between FirstName and LastName)
Computers and Technology
1 answer:
8090 [49]3 years ago
8 0

Answer:

   public static String ufnFullName(String Fname, String Lname){

       String FullName = Fname+" "+Lname;

       return  FullName;

   }

Explanation:

Using Java programming language, the function is created to accept two String parameters (Fname and Lname)

These are concatenated into a new String FullName and returned by the function

See below a complete code that prompts users to enter value for first and last names then calls this method to display the full name

<em>import java.util.Scanner;</em>

<em>public class FullName {</em>

<em>    public static void main(String[] args) {</em>

<em>        System.out.println("Enter First Name");</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        String Fname = in.next();</em>

<em>        System.out.println("Enter Last Name");</em>

<em>        String Lname = in.next();</em>

<em />

<em>        System.out.println("Your Full Name is "+ufnFullName(Fname,Lname));</em>

<em>    }</em>

<em>    public static String ufnFullName(String Fname, String Lname){</em>

<em>        String FullName = Fname+" "+Lname;</em>

<em>        return  FullName;</em>

<em>    }</em>

<em>}</em>

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Monster Collector
Lera25 [3.4K]

Answer:

In java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int monsternum, usernum;

 int count = 0;

 Random rand = new Random();

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

 for(int i =0;i<2;i++){

     monsternum = rand.nextInt(5);  

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

     usernum = input.nextInt();

     if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  }

 else{      System.out.println("You almost had it, but the monster escaped.");  }

 

 }

 System.out.println("There are no more monsters to encounter!");

 System.out.println("You caught "+count+" monsters of 2");

 if(count!=2){      System.out.print("Keep training to be the very best!");  }

 else{      System.out.print("You're the monster collector master!");  }

}

}

Explanation:

This declares monster and user number as integers

 int monsternum, usernum;

Initialize count to 0

 int count = 0;

Call the random object

 Random rand = new Random();

Create a string array to save the monster names

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

Iterate for the 2 monsters

 for(int i =0;i<2;i++){

Generate a monster number

     monsternum = rand.nextInt(5);  

Prompt the user to take a guess

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

Get user guess

     usernum = input.nextInt();

If monster number and user guess are equal, congratulate the user and increase count by 1

<em>      if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  } </em>

If otherwise, prompt the user to keep trying

<em>  else{      System.out.println("You almost had it, but the monster escaped.");  }  </em>

<em>  } </em>

Print no monsters again

 System.out.println("There are no more monsters to encounter!");

Print number of monsters caught

 System.out.println("You caught "+count+" monsters of 2");

Print user score

<em>  if(count!=2){      System.out.print("Keep training to be the very best!");  } </em>

<em>  else{      System.out.print("You're the monster collector master!");  } </em>

5 0
3 years ago
(word excel)
Aloiza [94]
D is the answer to that problem
7 0
3 years ago
Write a C++ program to find if a given array of integers is sorted in a descending order. The program should print "SORTED" if t
LenKa [72]

Answer:

The cpp program for the given scenario is as follows.

#include <iostream>

#include <iterator>

using namespace std;

int main()

{

   //boolean variable declared and initialized  

   bool sorted=true;

   //integer array declared and initialized

   int arr[] = {1, 2, 3, 4, 5};

   //integer variables declared and initialized to length of the array, arr

   int len = std::end(arr) - std::begin(arr);

       //array tested for being sorted

    for(int idx=0; idx<len-1; idx++)

    {

        if(arr[idx] < arr[idx+1])

           {

               sorted=false;

            break;

           }

    }

    //message displayed  

    if(sorted == false)

     cout<< "UNSORTED" <<endl;

 else

    cout<< "UNSORTED" <<endl;

return 0;

}

OUTPUT

UNSORTED

Explanation:

1. An integer array, arr, is declared and initialized as shown.

int arr[] = {1, 2, 3, 4, 5};

2. An integer variable, len, is declared and initialized to the size of the array created above.

int len = std::end(arr) - std::begin(arr);

3. A Boolean variable, sorted, is declared and initialized to true.

bool sorted=true;  

4. All the variables and array are declared inside main().

5. Inside for loop, the array, arr, is tested for being sorted or unsorted.  The for loop executes over an integer variable, idx, which ranges from 0 till the length of the array, arr.

6. The array is assumed to be sorted if all the elements of the array are in descending order.

7. If the elements of the array are in ascending order, the Boolean variable, sorted, is assigned the value false and for loop is exited using break keyword. The testing is done using if statement.

8. Based on the value of the Boolean variable, sorted, a message is displayed to the user.

9. The program can be tested for any size of the array and for any order of the elements, ascending or descending. The program can also be tested for array of other numeric data type including float and double.

10. All the code is written inside the main().

11. The length of the array is found using begin() and end() methods as shown previously. For this, the iterator header file is included in the program.

4 0
3 years ago
What is the most consistent item regardless of the software used in BI?
vodomira [7]

Answer Explanation:

Business intelligence is defined as the strategies and technologies used by companies for the data analysis of business information it tell us also about predictive views of business operation.

THE MOST CONSISTENT ITEMS REGARDLESS OF SOFTWARE USED IN BI ARE :

  • data analyst has the most responsibility of BI he is the most important part of BI
  • It is the interconnected process of inspection changing and modeling
  • data analysis is hugely aided by data mining
5 0
3 years ago
A research study does not need to be well designed to be effective.<br> False<br> O True
Sedbober [7]
Answer:

true

Remember to drink water!!
7 0
3 years ago
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