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morpeh [17]
3 years ago
15

Create and test a user-defined function named ufnFullName that combines the values of the two parameters named FirstName and Las

tName into a concatenated name field FullName, which is formatted as FirstName LastName (including a space between FirstName and LastName)
Computers and Technology
1 answer:
8090 [49]3 years ago
8 0

Answer:

   public static String ufnFullName(String Fname, String Lname){

       String FullName = Fname+" "+Lname;

       return  FullName;

   }

Explanation:

Using Java programming language, the function is created to accept two String parameters (Fname and Lname)

These are concatenated into a new String FullName and returned by the function

See below a complete code that prompts users to enter value for first and last names then calls this method to display the full name

<em>import java.util.Scanner;</em>

<em>public class FullName {</em>

<em>    public static void main(String[] args) {</em>

<em>        System.out.println("Enter First Name");</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        String Fname = in.next();</em>

<em>        System.out.println("Enter Last Name");</em>

<em>        String Lname = in.next();</em>

<em />

<em>        System.out.println("Your Full Name is "+ufnFullName(Fname,Lname));</em>

<em>    }</em>

<em>    public static String ufnFullName(String Fname, String Lname){</em>

<em>        String FullName = Fname+" "+Lname;</em>

<em>        return  FullName;</em>

<em>    }</em>

<em>}</em>

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Ne4ueva [31]

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

Kindly check the attached image below for the code output.

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Answer:

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Explanation:

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