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morpeh [17]
3 years ago
15

Create and test a user-defined function named ufnFullName that combines the values of the two parameters named FirstName and Las

tName into a concatenated name field FullName, which is formatted as FirstName LastName (including a space between FirstName and LastName)
Computers and Technology
1 answer:
8090 [49]3 years ago
8 0

Answer:

   public static String ufnFullName(String Fname, String Lname){

       String FullName = Fname+" "+Lname;

       return  FullName;

   }

Explanation:

Using Java programming language, the function is created to accept two String parameters (Fname and Lname)

These are concatenated into a new String FullName and returned by the function

See below a complete code that prompts users to enter value for first and last names then calls this method to display the full name

<em>import java.util.Scanner;</em>

<em>public class FullName {</em>

<em>    public static void main(String[] args) {</em>

<em>        System.out.println("Enter First Name");</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        String Fname = in.next();</em>

<em>        System.out.println("Enter Last Name");</em>

<em>        String Lname = in.next();</em>

<em />

<em>        System.out.println("Your Full Name is "+ufnFullName(Fname,Lname));</em>

<em>    }</em>

<em>    public static String ufnFullName(String Fname, String Lname){</em>

<em>        String FullName = Fname+" "+Lname;</em>

<em>        return  FullName;</em>

<em>    }</em>

<em>}</em>

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Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;

int main()//defining main method

{

int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value

int i,sum=0;//defining integer variable

for(i=0;i<10;i++)//defining loop for count value

{

   if(x[i]%2==1)//defining if block to check odd value

   {

       sum=sum+x[i];//add value in sum variable

   }

}

cout<<sum;//print sum

return 0;

}

Output:

31

Explanation:

In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.

In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.

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3 years ago
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Answer:

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Air bags are always safe. A. True<u> B. False</u>

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The quiz program is an illustration of loops and conditional statements

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  • Conditional statements are used to make decisions

<h3>The quiz program</h3>

The quiz program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

int main(){

   //This prints the instruction

   cout<<"Enter T/t for True; F/f for False\n";

   //This initializes the question

   string questions[5] = { "Q1", "Q2", "Q3", "Q4", "Q5"};

   //This initializes the correct options

   char options[5] = { 'T','T','F','F','T'};

   //This declares the user response

   char opt;

   //This initializes the score to 0

   int score = 0;

   //This loop is repeated 5 times

   for (int i = 0; i < 5; i++){

       //This prints the current question

       cout << i + 1 <<". "<<questions[i]<<"\nAnswer: ";

       //This gets the user response

       cin>>opt;

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       }

   }

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   cout<<"Score: "<<score;

   return 0;

}

Read more about loops at:

brainly.com/question/19347842

7 0
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NikAS [45]

Answer:

C++.

Explanation:

<em>Code snippet.</em>

#include <map>

#include <iterator>

cin<<N;

cout<<endl;

/////////////////////////////////////////////////

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for (int i = 0; i < N; i++) {

   cin<<name;

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   cout<<endl;

   contacts.insert(pair<string, string> (name, number));

}

/////////////////////////////////////////////////////////////////////

map<string, string>::iterator it = contacts.begin();

while (it != contacts.end())  {

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   number = it->second;

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}

/////////////////////////////////////////////////////////////////////////////////////////////////////////

I have used a C++ data structure or collection called Maps for the solution to the question.

Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.

8 0
3 years ago
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