All categories

3 years ago

- the following functions.

Mathematics

1 answer:

77julia77 [94]3 years ago

4 0

Answer:

(f+g)(1)

equals

Step-by-step explanation:

(f+g)(1) is f(1)+g(1).

f(1) means what y corresponds to x=1 so f(1)=-1.

g(1) means what y corresponds to x=1 so g(1)=4.

So (f+g)(1)=f(1)+g(1)=-1+4=3.

You might be interested in

If 15/3 greater than 7, then 15/7 is less than 3 true or false

Ludmilka [50]

Answer:

True

Step-by-step explanation:

15/7 is about 2.14 which is less than 3

3 0

3 years ago

Write 6.93 repeating a mixed number in simplest form.<br> 6.93 =?

Sergeu [11.5K]

Answer:

$6\frac{93}{100} = \frac{693}{100}$

Step-by-step explanation:

Turn 6.93 into a fraction: $6\frac{93}{100}$
To turn into a mixed number, first multiply 6 and 100, then add 93. Put 693 over 100: $\frac{693}{100}$

I hope this helps!

3 0

4 years ago

Read 2 more answers

I took notes and went back through the lesson but I can't get it. Help, please!!!

aliina [53]

Answer:

Step-by-step explanation:

▪Picture 1. x = 28

$\frac{x}{42} = \frac{10 + x}{57} \\ 42(10 + x) = 57x \\ 420 + 42x = 57x \\ \frac{ \: \: \: \: \: \: \: \: \: \: \: - 42x = - 42x}{ \frac{420}{15} = \frac{15x}{15} } \\ \\ 28 = x$

▪Picture 2. I don't know what in trying to solve.

▪Picture 3.

•ABC = 50

•DEF = 95

•GHI = 65

•JKL = 55

▪Picture 4. I dont know how to do that

4 0

3 years ago

From Euler’s relation eiθ = cosθ + isinθ,

adelina 88 [10]

Answer:

(a) The graphic representation is in the attached figure.

(b) $\cos(\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$ .

(c) $\sin(\theta) = \frac{e^{i\theta} - e^{-i\theta}}{2i}$ .

Step-by-step explanation:

(a) Given a complex number $e^{i\theta}$ we know, from Euler's formula that $e^{i\theta} = \cos(\theta)+i\sin(\theta)$ . So, it is not difficult to notice that

$|e^{i\theta}|^2 = \cos^2(\theta)+\sin^2(\theta) =1$

so it is on the unit circumference. Also, notice that the Cartesian representation of the complex number is $(\cos(\theta), \sin(\theta))$ .

Now,

$e^{-i\theta} = \cos(\theta)+i\sin(-\theta) = \cos(\theta)-i\sin(\theta)$ .

Notice that $e^{-i\theta}$ has the same modulus that $e^{i\theta}$ , so it is on the unit circumference. Beside, its Cartesian representation is $(\cos(\theta), -\sin(\theta))$ .

So, the points $(\cos(\theta), \sin(\theta))$ and $(\cos(\theta), -\sin(\theta))$ are symmetric with respect to the X-axis. All this can be checked in the attached figure.