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larisa86 [58]
3 years ago
11

- the following functions.

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0

Answer:

(f+g)(1)

equals

3

Step-by-step explanation:

(f+g)(1) is f(1)+g(1).

f(1) means what y corresponds to x=1 so f(1)=-1.

g(1) means what y corresponds to x=1 so g(1)=4.

So (f+g)(1)=f(1)+g(1)=-1+4=3.

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Helppppppppp !!! Please!!!
Anettt [7]
The domain would be all real numbers if it’s infinite and I’m not 100% sure ab the range but I think 7??? Like 1 to -5
7 0
3 years ago
The value (in cents) of the change in a purse that contains twice as many nickels as pennies, five more dimes than nickels, and
nexus9112 [7]

Value of the pursue in cents: 131p+175

Step-by-step explanation:

Let's call:

p = number of pennies

The problem tells us that the pursue contains twice as many nickels as pennies, so the number of nickels is

n=2p

Also, the pursue contains five more dimes than nickels, so the number of dimes is

d=n+5=2p+5

And finally, the pursue contains as many quarters as dimes and nickels combained, so the number of quarters is

q=d+n=(2p+5)+2p=4p+5

The value of each type of coin is:

Penny: 1 cent

Nickel: 5 cents

Dime: 10 cents

Quarter: 25 cents

So, the total value of the pursue in cents is:

1p+5n+10d+25q

And substituting,

=p+5(2p)+10(2p+5)+25(4p+5)=\\p+10p+20p+50+100p+125=\\131p+175

So, this is the value of the change in the pursue in cents.

Learn more about expressions:

brainly.com/question/7014769

brainly.com/question/11007572

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8 0
3 years ago
Read 2 more answers
What is 3x+1? They say its really easy and I don't know how.
posledela

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{x = - 1 / 3}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{3x + 1}

Find: \textsf{The value of the unknown variable x}

Solution: In order to solve for x we need to isolate it with the first step being to subtract 1 from both sides and then we would divide both sides by 3 to give us the solution.

<u>Subtract 1 from both sides</u>

  • \textsf{3x + 1 = 0}
  • \textsf{3x + 1 - 1 = 0 - 1}
  • \textsf{3x = 0 - 1}
  • \textsf{3x = - 1}

<u>Divide both sides by 3</u>

  • \textsf{3x / 3 = - 1 / 3}
  • \textsf{x = - 1 / 3}

Therefore, the final answer would be that x is equal to -1/3.

5 0
2 years ago
Read 2 more answers
You solved a linear system with two equations and two variables and got the equation o=-8. how many solutions does the system of
Luda [366]
If you simplified a two-equation system and all variables were eliminated, two outcomes are possible.

If the final equation is a true equation, like 3=3, then the system has an <em>infinite number of solutions </em> (the equations graph the same line, and all points appear on both graphs)

If the final solution is a mathematically false equation, like 0=-8, the system has no solution. The lines are parallel and never intersect (have a solution)
3 0
4 years ago
In a building there are 30 cylindrical pillars. The radius of each pillar is 42 m and height is 7 m. Find the total cost of pain
SashulF [63]

Answer:

The total cost of painting the curved surface area of all pillars at the rate of Rs 10 per square meter is Rs.554400.

Step-by-step explanation:

Given : In a building there are 30 cylindrical pillars. The radius of each pillar is 42 m and height is 7 m.

To find : The total cost of painting the curved surface area of all pillars at the rate of Rs 10 per square meter ?

Solution :

Radius of each pillar r= 42 m

Height of each pillar h= 7 m

The curved surface area of each pillar is CSA=2\pi rh

Substitute the value,

CSA=2\times \frac{22}{7}\times 42\times 7

CSA=1848\ m^2

Area of 30 pillars is given by,

A=1848\times 30=55440\ m^2

The curved surface area of all pillars at the rate of Rs.10 per square meter.

The cost painting is C=55440\times 10=Rs.554400

Therefore, the total cost of painting the curved surface area of all pillars at the rate of Rs 10 per square meter is Rs.554400.

3 0
4 years ago
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