1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
satela [25.4K]
3 years ago
6

1 3/4 miles in 1/2 hour. What is your average speed?

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0
3 1/2 mph since you need to multiply it by 2 to get the miles per hour
You might be interested in
the sum of the measures of two exterior angles of a triangle is 272. what is the measure of the third exterior angles​
umka21 [38]

Answer.

Step-by-step explanation:

Given = sum of two exterior angle of a triangle is 272 .

rule of triangle is that each and every angle which are outside a triangle is 360.

so, 272 + x = 360

x = 360 - 272

x = 88

7 0
3 years ago
Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootInd
lora16 [44]

The logarithmic expression \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} can be expressed as \rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8).

Given to us

\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}

<h3>Which expression is equivalent to \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} ?</h3>

To solve the problem we will use the basic logarithmic properties,

\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}

Using the logarithmic property \rm log_a\dfrac{x}{y} = log_ax-log_ay,

=\rm log_w{(x^2-6)^4} - log_w{\sqrt[3]{x^2-8}}

Using the exponential property \sqrt[m]{a^n} = a^{\frac{n}{m}},

=\rm log_w{(x^2-6)^4} - log_w(x^2-8)^{\dfrac{1}{3}}

Using the logarithmic property \rm log_aB^x = xlog_aB,

=\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)

Hence, the logarithmic expression \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} can be expressed as \rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8).

Learn more about Logarithmic Expression:

brainly.com/question/7302008

5 0
3 years ago
31 workers are working on a construction site. 5 more workers work for company A than for company B. How many workers work for e
Alona [7]
13 I believe as 31-5=26/2=13 Hope you'll find this helpful
6 0
3 years ago
If your teacher is 50 years old, what is their age in seconds?
riadik2000 [5.3K]

Based on time conversion, the age of a teacher who is 50 years old in seconds is 1577880000 seconds.

<h3>What is the age of a teacher who is 50 years in seconds?</h3>

The age of the teacher in years is converted to seconds as follows:

  • 60 seconds = 1 minute
  • 60 minutes = 1 hour
  • 24 hours = 1 day
  • 3651/4 days = 1 year

Thus:

50 years to seconds will be:

50 × 365.25 × 24 × 60 × 60 = 1577880000 seconds.

Therefore, the age of a teacher who is 50 years old in seconds is 1577880000 seconds.

Learn more about about time conversion at: brainly.com/question/13893070

5 0
3 years ago
Which equation is NOT true when k = -18?
a_sh-v [17]

Answer:

a. po yung answer

follow me

3 0
3 years ago
Read 2 more answers
Other questions:
  • Simplify 3^-9/3^-12 Please answer quickly
    10·1 answer
  • Need Help Please, Stressing out :( and Thank you:)
    9·2 answers
  • Find the infinite sum of 10,5,2.5,1.25...
    8·2 answers
  • In a data set with a range of 55.1 to 102.8 and 300 observations, there are 207 data points with values less than 88.6. find the
    15·1 answer
  • Quincy ran from one corner of a field to the opposite corner, a distance of 100 yards. Then he ran along its length, a distance
    8·1 answer
  • How many rows of 6 are in 30
    7·2 answers
  • HELP!!! HELP!!!!! HELP!!!! Jacob earns $12 every 4 days for walking a dog.
    15·2 answers
  • Really simple math question, pls help
    7·2 answers
  • If a = - i and b = 3 , then find the value of the a ^ 2 * b in fully simplified form .
    9·1 answer
  • Penny buys 3 bouquets of flowers for $3 each and 4 bouquets for $2 each. Which expression gives the total cost of the bouquets t
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!