Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
He ran 1 meter in about .10 seconds
Hope this helps!
To answer the question, we utilize the given data and solve for the number of customers left in the store after every 1 hour interval.
Initially, there were 75 customers.
1:00 to 2:00 : 75 + 30 - 12 = 93
2:00 to 3:00 : 93 + 14 - 8 = 99
3:00 to 4:00 : 99 + 18 - 30 = 87
4:00 to 5:00 : If the store does not accept any more customers except those who are already inside then, all 87 must leave between 4:00 to 5:00 in order to empty out the store by 5:00
ANSWER: (a) 4:00 to 5:00
(b) 87 customers
C=<span>πd
C=</span><span>π*30
C=30</span>π<span>≈94.25 cm</span>
He owns his mother $0; Because $21.50 - $21.50 is Zero
