The location of the y value of R' after using the translation rule is -10
<h3>What will be the location of the y value of R' after using the translation rule? </h3>
The translation rule is given as:
(x + 4, y - 7)
The pre-image of R is located at (-17, -3)
Rewrite as
R = (-17, -3)
When the translation rule is applied, we have:
R' = (-17 + 4, -3 - 7)
Evaluate
R' = (-13, -10)
Remove the x coordinate
R'y = -10
Hence, the location of the y value of R' after using the translation rule is -10
Read more about translation at:
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Answer:
The linear term is -5x
Step-by-step explanation:
The linear term is the term that has the degree equal to 1.
The given function is
y = 2x^2 − 5x − 12
here 2x^2 = quadratic term i.e having degree 2
-5x = linear term i.e having degree 1
-12 = constant
so, The linear term is -5x
Parentheses first, 72-63 is 9 next multiply by 4 which is 36 the you’ll divide by 3 now you have 12 so multiply that by 6 and you get 72. Just a hint, another way to write that without using the multiply or the divided would be 6[4(72-63)/3] but either way you want is fine. Hope this helped :)
Hello from MrBillDoesMath!
Answer:
The first choice ( -12, 20)
Discussion:
Using matrix multiplication we find the equations:
1x + 1y = 8 (A)
2x + 3y = 36 (B)
Next, compute
2(A) - B =>
(2x + 2y) - (2x + 3y) = 2*8 - 36 =>
(2x - 2x) + ( 2y-3y) = 16 - 36 =>
-y = -20 =>
y = 20
Substituting this y value in (A) gives
x + 20 = 8 =>
x = 8 - 20 =>
x = -12
The answer is the first choice ( -12, 20)
Thank you,
MrB
