What situation can his diagram represent

PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!I will give brainliest !!!!!!!!!!!!!!Sam knows he will be waiting at least 80 minuets in line

sergiy2304 [10]

Answer:

4

Step-by-step explanation:

20 x 4 = 80

so 1 per 20 minuets,and 4, 20 min. magazines would mean he needs 4 to make it to 80

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!!!! ABCD is a parallelogram. Find x.

Diano4ka-milaya [45]

Answer:

here,x=123, is the answer.

4 0

3 years ago

In AEFG, F = 61 inches, ZF=79º and ZG=34°. Find the length of g, to the nearest 10th of an inch.

DENIUS [597]

Answer:

g ≈ 34.7 in

Step-by-step explanation:

The law of sines is useful for this:

f/sin(F) = g/sin(G)

Multiplying by sin(G), we have ...

g = f·sin(G)/sin(F) = (61 in)·sin(34°)/sin(79°)

g ≈ 34.7 in

7 0

3 years ago

The selling price of a refrigerator, is $ 796.40 . If the markup is 10 % of the dealer's cost, what is the dealer's cost of

8_murik_8 [283]

The final price (what it is selling for) is $796.40

The markup is 10% of the original price (the dealer's cost) , meaning that it is 10% more.

We need to find the original price.

We write this as an equation

The original price *110% = final price

This is because the original price is itself (100%) added with 10%

Plug in the known final price

Original Price * 110% = 796.40

Convert 110% to a decimal because the other numbers- such as the final price are also decimal numbers.

Convert 110% to a decimal by moving the decimal point up 2 spaces ( basically dividing it by 100)

110% = 1.1

So it is now

Original price *1.1 = 796.40

Divide both sides by 1.1 to isolate our unknown, the original price

Original price = $724

5 0

3 years ago

The Slow Ball Challenge or The Fast Ball Challenge.

cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

$Pitches = 7$

$P(Hit) = 80\%$

$Win = \$60$

$Lost = \$10$

Fast Ball Challenge

$Pitches = 3$

$P(Hit) = 70\%$

$Win = \$60$

$Lost = \$10$

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 7$ --- pitches

$x = 7$ --- all hits

$p = 80\% = 0.80$ --- probability of hit

So, we have:

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

$P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}$

$P(7) =1 * 0.80^7 * (1 - 0.80)^0$

$P(7) =1 * 0.80^7 * 0.20^0$

Using a calculator:

$P(7) =0.2097152$ --- This is the probability that he wins

i.e.

$P(Win) =0.2097152$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 -0.2097152$

$P(Lose) = 0.7902848$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.2097152 * \$60 + 0.7902848 * \$10$

Using a calculator, we have:

$Expected = \$20.48576$

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 3$ --- pitches

$x = 3$ --- all hits

$p = 70\% = 0.70$ --- probability of hit

So, we have:

$P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}$

$P(3) =1 * 0.70^3 * (1 - 0.70)^0$

$P(3) =1 * 0.70^3 * 0.30^0$

Using a calculator:

$P(3) =0.343$ --- This is the probability that he wins

i.e.

$P(Win) =0.343$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 - 0.343$

$P(Lose) = 0.657$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.343 * \$60 + 0.657 * \$10$

Using a calculator, we have:

$Expected = \$27.15$

So, we have:

$Expected = \$20.48576$ -- Slow ball

$Expected = \$27.15$ --- Fast ball

The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.

5 0

3 years ago