Question

The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h (t) = 300 minus 16 t squared. Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall?
h(3) – h(0)
h (three-thirds) minus h (zero-thirds)
StartFraction h (3) Over 3 EndFraction
StartFraction h (3) minus h (0) Over 3 EndFraction

Answer 1

Answer:

Average rate of fall = $\frac{h(3)-h(0)}{3}$

Step-by-step explanation:

Since they give you an expression for the position of the object as a function of time, one can derive the average velocity of the object during the first 3 seconds of the fall by estimating the position of the object at time 0, the position of the object at time 3 seconds, finding the displacement of the object (distance covered) in that interval of time (via a subtraction of these two quantities), and finally dividing this change by the elapsed time (3 seconds) thus using the concept that velocity is the quotient between distance covered over the elapsed time:

Average rate of fall = (h(3) - h(0))/ 3

Average rate of fall = $\frac{h(3)-h(0)}{3}$

Answer 2

Answer:

D

Step-by-step explanation: