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3 years ago

Solve the soultion .explian please x(2x- 5)=0

Mathematics

2 answers:

AysviL [449]3 years ago

7 0

$x(2x-5)=0\iff x=0\ \vee\ 2x-5=0\\\\x=0\ \vee\ 2x=5\\\\x=0\ \vee\ x=\frac{5}{2}\\\\x=0\ \vv\ x=2.5$

chubhunter [2.5K]3 years ago

6 0

$x(2x- 5)=0 \\x=0 \vee 2x-5=0\\
x=0 \vee 2x=5\\
x=0 \vee x=\frac{5}{2}$

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1 yard = 3 feet.

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a. closed under addition and multiplication

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d. closed under addition and multiplication

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Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

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$xy=(5m)(5n)=25mn=5(5mn)$

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$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

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Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

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Let $x,y$ ∈ A such that $x=-1,y=1$

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$x+y=-1+1=0$

So,

$x+y$ ∈ A

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