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pentagon [3]
3 years ago
10

Can someone please help me!!! thanks

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0
Y=-2 since using the hypotenuse leg theorem
Lynna [10]3 years ago
3 0
Since the two triangles are congruent, set the values of the legs equal to each other. x-y=x+2
-y=2
y=-2
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What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)
Alborosie

Answer:

Step-by-step explanation:

Using the distance formula,

AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\

So the perimeter is 4\sqrt{2}+7+2\sqrt{5}

3 0
2 years ago
Kevin wants to paint the box with a new color. He must determine the surface area of the box to caculate the amount of paint to
tankabanditka [31]

Answer:

Whatever he wants, he's painting so he can paint however he wants

7 0
3 years ago
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Two cities are 3 1/2 inches apart on a map the map scale says that 1/4 inch is 1 mile how many miles apart are the two cities
maria [59]

Answer:

every 1/4 inch on the map is 1 mile.

You need to find the number of 1/4 inches there are in 3 1/2 inches.

There are four 1/4 inches per inch.

3 x 4 = 12

There are two 1/4 inches in 1/2 inch.

12+2 = 14

The cities are 14 miles apart.

7 0
2 years ago
A patient with diabetes self-injected 5 units of regular insulin and 15 units of NPH insulin at 0800. When should the nurse asse
GalinKa [24]

Answer:

Hypoglycemia would sign at 1,000

Step-by-step explanation:

We know that a short-acting insulin (Regular insulin) work at last for 2 to 3 hours

Also intermediate acting insulin (NPH) insulin crests in 4 to 10 hours.

So, nurse assess this patient for signs of hypoglycemia 1000 to 1600

3 0
3 years ago
This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)
beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}

But equation of a hyperbola is given as

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Substituting the values of a, b, h and k, we have

\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}

Hence the answer is

\frac{x^2}{1}-\frac{y^2}{3}=1

5 0
11 months ago
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