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2 years ago

Can someone please help me!!! thanks

Mathematics

2 answers:

zubka84 [21]2 years ago

8 0

Y=-2 since using the hypotenuse leg theorem

Lynna [10]2 years ago

3 0

Since the two triangles are congruent, set the values of the legs equal to each other. x-y=x+2
-y=2
y=-2

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3 years ago

It was cloudy 12 out of 30 days in April. Which value is equivalent to the fraction of

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any of the below:

Step-by-step explanation:

12/30

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2 years ago

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There are two thousand girls and one thousand boys at a university.For every girl with glasses there are two boys who were glass

e-lub [12.9K]

Answer:

200

Step-by-step explanation:

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3 years ago

Find the slope of the line 7x-4y=10

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Answer:

The slope is $m=(7/4)$

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

In this problem we have

$7x-4y=10$

Convert to slope intercept form

Isolate the variable y

$4y=7x-10$

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3 years ago

What is the equation of the circle with center (-3,1) that passes through the point (-5, 3)?

Natali5045456 [20]

Answer:

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by:

$(x-h)^2 + (y-k)^2 = r^2$

Given

Center = (h,k) = (-3,1)

=> h = -3

=> k = 1

The distance between the center of circle and the point through which the circle passes will be the radius.

The distance formula is given by:

$r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Given

$(x_1,y_1) = (-3,1)\\(x_2,y_2) = (-5,3)$

Putting the values in the formula

$r = \sqrt{(-5+3)^2+(3-1)^2}\\r = \sqrt{(-2)^2+(2)^2}\\r = \sqrt{4+4}\\r = \sqrt{8}$

Putting the values of h,k and r in general form of equation

$\{x-(-3)}^2\} +(y-1)^2 = (\sqrt{8})^2\\(x+3)^2+(y-1)^2 = 8$

Hence,

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

4 0

2 years ago