PLEASE HELP ME!

Mathematics

1 answer:

lawyer [7]3 years ago

6 0

At the beining, he has 76
that is at x=0
y=mx+76

find m
given
when x=2, y=100
find m

100=2m+76
minus 76 both sides
24=2m
divide both sides by 2
12=m

the equatin is

y=12x+76

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one number is 7 more than twice the other number. if the sum of the two numbers is 19, find the two numbers

topjm [15]

Answer:

4 and 15

Step-by-step explanation:

Let the two numbers be a and b.

The sum of the two is 19. Therefore:

$a+b=19$

One number (let's use a) is 7 <em>more</em> than twice the other. Thus:

$a=7+2b$

Solve for the system of equations. Substitute the second equation into the first:

$a+b=19\\(7+2b)+b=19$

Subtract 7 from both sides:

$2b+b=12$

Combine like terms:

$3b=12$

Divide by 3:

$b=4$

So, b is 4.

And since they add up to 19, this means that a is:

$a+b=19\\a+4=19\\a=15$

So our numbers are 4 and 15

And we are done :)

8 0

3 years ago

Write the ratio $150 : $450 : $750 in its simplest form.

Oliga [24]

Lets do

$\\ \Large\sf\longmapsto 150:450:750$

$\\ \Large\sf\longmapsto \frac{150}{ \dfrac{450}{750} } \\ \\ \Large\sf\longmapsto \frac{15}{ \dfrac{45}{75} } \\ \\ \Large\sf\longmapsto \frac{3}{ \dfrac{9}{15} } \\$