The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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- Your answer is no solution.
- Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
- 10x - 1 = 10x +4
- or, 10x - 10x = 4 + 5
- or, 0 = 9
- Hence, the equation has <em><u>no solution</u></em>.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
0.1
Step-by-step explanation:
When Juan cut a 1 lb loaf of banana bread into 6 slices, the weight of each slice forms a repeating decimal. A repeating decimal is a decimal number with repeating digit/s.
i.e 
= 0.166666666666666...
To express the total weight for each slice, he should write a bar over 6 to show that the number repeats.
i.e = 0.1
Note that has expressed that the division has 6 as the repeating digit in the decimal number.
Answer:
9
Step-by-step explanation:
21^2-19^2=80
sqaure root of 80 to the nearest 10th is
I’m guess you are looking for 751?
