Answer: With the help of a narrow beam of light, a glass prism, and a white wall it is possible to produce the band of seven colors using white light.
Explanation: White light is called as white because it consists of seven colors. The sunlight splits into seven colors namely violet, indigo, blue, green, orange, and red.
I believe only one atom of oxygen is in a molecule of acetaldehyde.
First solve the moles of oxgen present in the compound
mol O = 6.93 g O ( 1 mol O / 16 g O )
mol O = 0.43 mol H
then solve the moles of hydrogen present
mol H = ( 7.36 - 6.93) g H ( 1 mol H / 1 g H)
mol H = 0.43 mol H
so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
H2O2
Answer:
<em><u>PLZ</u></em><em><u> </u></em><em><u>MARK</u></em><em><u> </u></em><em><u>ME</u></em><em><u> </u></em><em><u>BRIANLIEST</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>REALLY</u></em><em><u> </u></em><em><u>WANT</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>PLZZZZZZ</u></em><em><u> </u></em><em><u>ISS</u></em><em><u> </u></em><em><u>GARIB</u></em><em><u> </u></em><em><u>KI</u></em><em><u> </u></em><em><u>DUA</u></em><em><u> </u></em><em><u>LAGEGI</u></em><em><u> </u></em><em><u>YARR</u></em><em><u> </u></em><em><u>PLZ</u></em>
Explanation:
<em>Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.</em>
<h2>I THINK IT IS 200 </h2><h2 /><h2>PROBABLY THIS HELP </h2>