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const2013 [10]
3 years ago
5

Molarity of a salt water solution of "0.47" moles of NaCl dissolved in a volume of 0.25L

Chemistry
1 answer:
asambeis [7]3 years ago
5 0

Answer:

1.88 M

Explanation:

The following data were obtained from the question:

Mole of NaCl = 0.47 mole

Volume of solution = 0.25L

Molarity =?

Molarity is defined as the mole of solute per unit litre of the solution. It can represented mathematically as:

Molarity = mole /Volume

Using the above formula, the molarity of the salt water solution can be obtained as follow:

Molarity = 0.47/0.25

Molarity = 1.88 M

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Yes, they do. The process described is a chemical reaction and it implies the change of nature of reactants and, of course, the change of its properties.
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Magnesium and Hydrochloric acid (HCl) react to form magnesium chloride (MgCl2) and hydrogen gas. If you started with 65.8 g of m
DiKsa [7]

Answer:

Cl

Explanation:

n for Mg=m:Mm

=65.8:24

=2.74mol

n for Cl=m:Mm

=45.7:70

=0.65mol

According to the <em>number of moles</em> we can say that the limiting reagent is Cl as it has few moles.

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What subatomic particle is specifically responsible for combining the atoms together to form a new substance?
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3 0
3 years ago
The freezing point of pure benzene (C₆H₆) is 5. 49 °C. The freezing point of a solution made using toluene (C₇H₈) in benzene is
Irina18 [472]

The molality of the toluene is 1.46 mol/kg.

<h3>What is molality?</h3>

The molality of a solution is its molal concentration. Molal concentration is denoted by m. It is the mol of solute dissolves in 1 Kg solvent.

The depression at freezing point is directly proportional to the molality of the solution. The equation we use for this type of problem is:

ΔT=iKm f_m

Where,  ΔT f_m is depression at freezing point, i is Van't hoff factor, m is molality and K_f is the freezing point depression constant.

Toluene is a non-electrolyte and so the value of i for this is 1.

Depression at a freezing point is given as -13.0^0 and the K_f is given as 5.12. So, we could calculate the molality of the solution using the equation written above.

Let's plug in the values in the equation:

ΔT=iKmf_m

-7.51 =1 x5. 12 xm

m = \frac{7.51}{5. 12}

m = 1.46 m

It means the molality of the solution is 1.46 mol/kg.

Hence, the molality of the solution is 1.46 mol/kg.

Learn more about the molality of the solution here:

brainly.com/question/12123356

#SPJ1

3 0
2 years ago
A sample of trifluoroacetic acid, C2HF3O2, contains 26.5 g of oxygen. Calculate the mass of the trifluoroacetic acid sample.
Yuki888 [10]

Answer:

94.3 grams

Explanation:

MW of C2HF3O2 is 114g/mol

MW of oxygen in C2HF3O2 is 32g/mol

% composition of oxygen in C2HF3O2 = 32/114 × 100 = 28.1%

Mass of oxygen = 26.5 grams

Mass of trifluoroacetic acid = 26.5/0.281 = 94.3 grams

6 0
3 years ago
Read 2 more answers
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