Answer:
The critical value for this hypothesis test is 6.571.
Step-by-step explanation:
In this case the professor wants to determine whether the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes.
Then the variance will be,
The hypothesis to determine whether the population variance is less than 25.0 minutes or not, is:
<em>H</em>₀: The population variance is not less than 25.0 minutes, i.e. <em>σ²</em> = 25.
<em>Hₐ</em>: The population variance is less than 25.0 minutes, i.e. <em>σ²</em> < 25.
The test statistics is:

The decision rule is:
If the calculated value of the test statistic is less than the critical value,
then the null hypothesis will be rejected.
Compute the critical value as follows:

*Use a chi-square table.
Thus, the critical value for this hypothesis test is 6.571.
Hello There!
<u><em>n - d = 0</em></u>
<u><em>5n+10d = 90</em></u>
<u><em>----------------------</em></u>
<u><em>n-d = 0</em></u>
<u><em>n+2d = 18</em></u>
<u><em>-------------------</em></u>
<u><em>Subtract and solve for "d":</em></u>
<u><em>3d = 18</em></u>
<u><em>d = 6 (# of dimes)</em></u>
<u><em>n = d = 6 (# of nickels)</em></u>
Answer:
248
Step-by-step explanation:
A + B = 180 -EQ 1
A + C =180 -EQ 2
B =124
BY EQ1 :
A = 180 - 124 =56
C = 180 -56 =124
B + C = 124+124
=248