Question

Meteorologists look for weather trends across US states in the same geographical region. Kentucky and Illinois share a border. The average annual temperatures (°F) from 1991 to 2000 for Kentucky were 57.5, 55.1, 52.2, 55.6, 55.6, 54.4, 54.5, 58.3, 57.3, and 55.7. The average annual temperatures (°F) from 1991 to 2000 for Illinois were 53.7, 51.9, 50.9, 51.8, 51.4, 49.9, 50.8, 55.0, 53.3, and 52.0. Use the statistics calculator to determine the measures of center for Kentucky.

Answer 1

The average annual temperatures (°F) from 1991 to 2000 for Kentucky were 57.5, 55.1, 52.2, 55.6, 55.6, 54.4, 54.5, 58.3, 57.3, and 55.7.

We have to evaluate the measures of center.

Firstly, we will calculate the mean.

Mean = (Sum of all the observations)/ (Total number of observations)

Mean =  $\frac{57.5+55.1+52.2+55.6+55.6+54.4+54.5+58.3+57.3+55.7}{10}$

= $\frac{556.2}{10}$

= 55.62

Now, we will calculate mode.

Mode is a statistical term that refers to the most frequently occurring number found in a set of numbers.

Consider the data 57.5, 55.1, 52.2, 55.6, 55.6, 54.4, 54.5, 58.3, 57.3, and 55.7.

Mode = 55.6

Now, we will calculate the median.

Firstly, we will arrange in the ascending order.

52.2, 54.4, 54.4,55.1 ,55.6, 55.6, 55.7, 57.3, 57.5, 58.3

Since there are 10 terms.

Median = $\frac{n}{2}$th observation

Median = 5th observation.

Since, the 5th observation is 55.6.

Therefore, the median is 55.6

Answer 2

Answer:

Kentucky mean *55.62* Illinois mean=52.07

Kentucky mean *55.60* iliinois mean=51.85

Both measures of center for Kentucky are *greater than* those of iliinois

Step-by-step explanation:

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