It would be. 2Fe + 3O2 ——> 2Fe03. You have to make oxygen 6 on both sides in order to balance, then you can do Fe. Which on the right would be 2 by making oxygen 6. Then add the 2 to the other side to balance it.
In an acid and base neutralization reaction, the products are salt and water.
Answer:Acids. :H2CO3, H3PO4,H3OBR
CH3COOH,
Bases MgO,NH4OH,CaOH
Neutral species; CaC,CaCO3,ClO3
Explanation:
Answer:
We need 4.28 grams of sodium formate
Explanation:
<u>Step 1:</u> Data given
MW of sodium formate = 68.01 g/mol
Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L
pH = 3.74
Ka = 0.00018
<u>Step 2:</u> Calculate [base)
3.74 = -log(0.00018) + log [base]/[acid]
0 = log [base]/[acid]
0 = log [base] / 0.42
10^0 = 1 = [base]/0.42 M
[base] = 0.42 M
<u>Step 3:</u> Calculate moles of sodium formate:
Moles sodium formate = molarity * volume
Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles
<u>Step 4:</u> Calculate mass of sodium formate:
Mass sodium formate = moles sodium formate * Molar mass sodium formate
Mass sodium formate = 0.063 mol * 68.01 g/mol
Mass sodium formate = 4.28 grams
We need 4.28 grams of sodium formate
