Answer:
Explanation:
Hello,
On the attached document, you will find the procedure regarding the required volume. At first, it is necessary to know atoms by day produced, by using a rule of three. Subsequently, we compute the moles per day and finally the volume via the ideal gas equation at STP.
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Sulfur has 6 electrons, so we put 6 in the first spot.
Oxygen has 6 electrons too, but since there are 3, we would multiply 6 times 3 , which equals 18, then add that too.
The 2 is added because there is that negative 2 at the top of the formular, which indicates the presence of two extra valence electrons.
the equation would be
6 + 18 + 2 = 26
Answer:
6. Double replacement "DR"
7. Double replacement "DR"
8. Combustion "C"
9. Single replacement "SR"
10. Decomposition "D"
Explanation:
- number 6 and 7 are double replacements because if you look at the compounds in the reactants vs the products, it is evident that there has been a replacement between Na & K in number 6 and Mg & Li in number 7, a "DR" occurs when the anions and cations in 2 molecules switch places to form 2 new compounds.
- number 8 is a combustion reaction because a combustion reaction occurs when oxygen is combined with another compound to form water and carbon dioxide (H2O & CO2).
- number 9 is a single replacement reaction because the Pb and Fe have simply switched places, "SR" are when an element trades with another to form a new compound and the element that was swapped.
- number 10 is a decomposition because it can be observed that the compound in the products is being broken down into the molecules or compounds that it is made up of, started with one and finished with 2
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.
HNO2 <-> H(+) + NO2(-)
Next, create an ICE table
HNO2 <--> H+ NO2-
[]i 0.230M 0M 0M
Δ[] -x +x +x
[]f 0.230-x x x
Then, using the concentration equation, you get
4.5x10^-4 = [H+][NO2-]/[HNO2]
4.5x10^-4 = x*x / .230 - x
However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable,
assume 0.230-x ≈ 0.230
4.5x10^-4 = x^2/0.230
Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.
We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.
Then to find percent dissociation, you do final concentration/initial concentration.
0.01M/0.230M = .0434 or
≈4.34% dissociation.