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3 years ago

What are the products of a neutralization reaction?

Chemistry

2 answers:

vfiekz [6]3 years ago

3 0

In an acid and base neutralization reaction, the products are salt and water.

sladkih [1.3K]3 years ago

3 0

<u>Answer:</u> The products of a neutralization reaction are salt and water.

<u>Explanation:</u>

Neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

The general equation for the above reaction follows:

$HX+BOH\rightarrow BX+H_2O$

<u>For Example:</u> Reaction of HCl and NaOH follows

$HCl+NaOH\rightarrow NaCl+H_2O$

Hence, the products of a neutralization reaction are salt and water.

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In a chemical process, three bottles of a standard fluid are emptied into a larger container. A study of the individual bottles

Setler79 [48]

Answer:

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3 years ago

Which element had the longest effect on human history?

Dovator [93]

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3 years ago

Molarity of 0.50 mol sugar in 270 mL of solution.

EastWind [94]

<h3>Answer:</h3>

1.85 M

<h3>Explanation:</h3>

<u>We are given;</u>

Number of moles as 0.50 mol
Volume of the solution is 270 ml

But, 1000 mL = 1 L

Thus, volume of the solution is 0.27 L

We are required to calculate the molarity of the solution;

Molarity refers to the concentration of a solution in moles per liter.
It is calculated by dividing number of moles with the volume.

Molarity = Moles ÷ Volume

In this case;

Molarity = 0.50 moles ÷ 0.27 L

= 1.85 Mol/L or 1.85 M

Therefore, molarity of the solution is 1.85 M

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3 years ago

It's 32°F (0°C) outside under normal atmospheric conditions (1 atm) at a stunt

Korolek [52]

The volume of the balloon is approximately 2652 liters.

<h3>How to determine the volume occupied by the gas in a balloon </h3>

Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass ( $M$ ), in kilograms per kilomole, and mass of the gas ( $m$ ), in kilograms. The volume occupied by the gas ( $V$ ), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:

$V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}$ (1)

Where:

$R_{u}$ - Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
$T$ - Temperature, in Kelvin
$P$ - Pressure, in kilopascals

If we know that $m = 0.239\,kg$ , $R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}$ , $T = 273.15\,K$ , $P = 101.325\,kPa$ and $M = 2.02\,\frac{kg}{kmol}$ , then the volume of the balloon is:

$V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}$

$V = 2.652\,m^{3}$ ( $2652\,L$ )

The volume of the balloon is approximately 2652 liters. $\blacksquare$

To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877

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2 years ago

Who no this i need help i need to pass to the next grade

Hitman42 [59]

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3 years ago