The new concentration of the solution is 0.016 M
<h3>Dilution</h3>
From the question, we are to determine the concentration of the new solution prepared from question 4.
NOTE: Question is provided below
From question 4, the concentration of the sodium chloride solution is 0.200M
Now, to determine the new concentration,
Using the dilution law
C₁V₁ = C₂V₂
Where
C₁ is the initial concentration
V₁ is the initial volume
C₂ if the final concentration
and V₂ is the final volume
Then,
C₁ = 0.200 M
V₁ = 10.00 mL
C₂ = ?
V₂ = 125.00 mL
Then,
0.200 × 10.00 = C₂ × 125.00
C₂ = 0.016 M
Hence, the new concentration of the solution is 0.016 M
Question 4:
Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution
Learn more on Dilution here: brainly.com/question/24881505
Answer:
5.95g
Explanation:
1 
= 1000 mL
∴ 100 mL = 100 ÷ 1000 = 0.1
Volume = <u>0.1 </u><u />
Concentration = <u>0.5 M</u>
Concentration = 
0.5 = 
No. of moles = 0.5 x 0.1 = <u>0.05 moles</u>
No. of moles = 
Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)
0.05 = 
x = 119 × 0.05 = 5.95g
Answer:
In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation
Explanation:
