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alexira [117]
3 years ago
12

Which two chemical elements make up earths atmosphere

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
7 0

Earth's atmosphere is 78% nitrogen, 21% oxygen, 0.9% argon, and 0.03% carbon dioxide with very small percentages of other elements. Our atmosphere also contains water vapor.

hope this helps!

(:

You might be interested in
5. Which of the following correctly shows alpha decay?
lorasvet [3.4K]

Answer:

U --> Th + He

Explanation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4  and atomic number less than 2 as compared to parent atom the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  

3 0
4 years ago
The density of honey is 1.42 g/mL. If you poured honey into a glass of water, would it sink to the bottom or float on top? Expla
m_a_m_a [10]

Answer:

The honey would sink to the bottom

Explanation:

A simple interpretation of Archimedes' principle is that, in water, the bodys with density lower than that of water will float on top of the water (That is, density <1g/mL). In the other way, a body with density higher than that of water will sink to the bottom.

As density of honey is higher than density of water:

<h3>The honey would sink to the bottom</h3>
3 0
3 years ago
An electron in an atom is known to be in a state with magnetic quantum number . What is the smallest possible value of the princ
nlexa [21]

Answer:

Hi

Each electron in an atom is characterized by four numbers that arise from the resolution of Schrödinger's equations. These numbers are called quantum numbers. Each energy level corresponds to a main known quantum number, which is represented by the letter n. This number gives an idea of the location of an energy level with respect to the nucleus. The higher n, the mayor will be the energy of that level and the farther away from the nucleus is removed.

In each energy level there may be sub-levels. Each of them is specified by another quantum number called secondary, specified with the letter l. The value of this quantum number can vary from zero to n-1. For example, in the first energy level, the quantum number can only take a value that is zero, while in the second level, it can take a value between zero or one. Then, it can be said that the values of the quantum number n indicate the size of the orbital, that is, its proximity to the nucleus; and the values of the quantum number l variables the orbital:

• If l = 0, the orbital is of type s.

• If l = 1, the orbitals are of type p.

• If l = 2, the orbitals are of type d.

• If l = 3, the orbitals are of type f.

Explanation:

8 0
3 years ago
Please help!!! Important. (Click on photo)I’ll give branliest and 30 points! (I put it as chemistry but it’s science)
stepan [7]

Answer:

When the moon moves between the sun for solar eclipse

When the earth moves between the sun and moon

(Extremely sorry if im wrong)

Explanation:

6 0
3 years ago
Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0
3 years ago
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