None of the given options are correct, and the correct answer is 174 K.
<u>Explanation:</u>
Mass of N = 41.6 g
Moles = ![$\frac{given mass}{molar mass}](https://tex.z-dn.net/?f=%24%5Cfrac%7Bgiven%20mass%7D%7Bmolar%20mass%7D)
=
= 1.5 moles
Pressure, P = 815 mm Hg = 1.07 atm
Volume, V = 20 L
R = gas constant = 0.08205 L atm mol⁻¹ K⁻¹
Temperature, T = ? K
We have to use the ideal gas equation,
PV = nRT
by rearranging the equation, so that the equation becomes,
T =
Plugin the above values, we will get,
T = ![$\frac{1.07 \times 20}{1.5 \times 0.08205}](https://tex.z-dn.net/?f=%24%5Cfrac%7B1.07%20%5Ctimes%2020%7D%7B1.5%20%5Ctimes%200.08205%7D)
= 174 K
So the temperature of the nitrogen gas is 174 K.