A species that is isoelectronic with the oxide ion will have the same electron configuration of electrons as as the oxide ion.
4 species that are isoelectronic with the oxide ion are F^(-), Ne, Na^(+), and Mg^(2+).
All of the electron configuration of these ions end at 2p⁶.
Answer:
A. 2.4 x 10¹⁴ J
Explanation:
m (mass) = 2.7 x 10⁻³ kg
c = 3.0 x 10⁸ m/s
Plug these numbers into the equation E=mc²
E=mc²
E= (2.7 x 10⁻³)(3.0 x 10⁸)²
E= 2.43 x 10¹⁴
So, the answer is A. 2.4 x 10¹⁴ J.
Answer:
i think true
Explanation:
lemme know if right if not sorry :))
The missing components in the table to the right are indicated with orange letters. Use the periodic table in the tools bar and this link Web Elements to fill in the corresponding values. A B C D E F G. 2. See answers. Log in to add ... F = 737.7kJ/mol. G = 495.8kJ/mol. Explanation: We are asked some of the ...
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