The value of quarters in the bowl on week 1 was &5
<em><u>The least amount of money you would need to invest per month is; $335</u></em>
<em><u>The anticipated rate of return on your investments is; 7%</u></em>
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- Amount to have been saved at the end of 10 years ≥ $40,000
Number of years of savings = 10 years.
- We want to find out the least amount to be invested per month.
There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.
- Thus, amount to be saved monthly = 40000/12 = $333.33
- Since the minimum amount he wants to save after 10 years is $40000, then we need to approximate the monthly savings in order.
Thus;
Monthly savings ≈ $335
- Now, for the anticipated rate of return on the investment, we know from S & P's that the benchmark on good rate of return for investment is a minimum of 7%.
- From online calculator, the worth of the investment after 10 years based on 7% rate of return yearly would be $57626.
Read more at; brainly.com/question/9187598
Answer: C
Step-by-step explanation:
You can write each term into a fraction.
![\sqrt[5]{x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E4%7D)
becomes 
When you multiply 2 terms with the same base, you add the exponents.
is also the same as ![x\sqrt[5]{x^3}](https://tex.z-dn.net/?f=x%5Csqrt%5B5%5D%7Bx%5E3%7D)
You get this because ![\sqrt[5]{x^8} =\sqrt[5]{x*x*x*x*x*x*x*x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E8%7D%20%3D%5Csqrt%5B5%5D%7Bx%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax%7D)
. When you pull out 5 os x, you are left with x³ on the inside.
Answer:
Should be 4/7
Hope it helps have a good day!
Answer: 243, 729
<u>Step-by-step explanation:</u>
1, 3, 9, 27, 81 is a geometric sequence where r = 3
a₁ = 1
a₂ = 1 x 3 = 3
a₃ = 3 x 3 = 9
a₄ = 9 x 3 = 27
a₅ = 27 x 3 = 81
To find the next two terms, multiply the previous term by 3:
a₆ = 81 x 3 = 243
a₇ = 243 x 3 = 729
