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Natalka [10]
3 years ago
13

Is it possible for two vertical angles to also be complementary angles? Explain why or why not. If so, find the measure of these

angles.
Mathematics
1 answer:
enot [183]3 years ago
8 0

Vertical angles are congruent.  Complementary angles add to 90 degrees.  So if the vertical angles are each half, 45 degrees, they'll be congruent and complementary.

Answer: 45 degrees

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Which of the following is an example of an improper fraction?
mote1985 [20]
The answer is D. 10/3 
The numerator cannot be more than the denominator.
3 0
3 years ago
Read 2 more answers
What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

8 0
3 years ago
I don’t understand this
Oxana [17]

You have to multiply whats outside the parenthesis with everything that is inside, so

x^{-3}y^0.(x^2-3x^5y^4)

x^{-3}y^0.x^2-x^{-3}y^0.3x^5y^4

Multiplication of same bases we sum the exponents

x^{-3+2}y^0-3x^{-3+5}y^{0+4}

x^{-1}.1-3x^2y^4

x^{-1}-3x^2y^4

Alternative B.

7 0
3 years ago
() + -8= -6 what is the awnser
Mariana [72]

Answer:x=2

Step-by-step explanation:

change () to x

x + -8= -6

-6+8=2

x=2

5 0
3 years ago
NEED HELP FOR EXAMS TOMORROW
alexandr1967 [171]

Answer:

also got exams

Step-by-step explanation:

good luck bro

7 0
2 years ago
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