Answer:
a= 4
b= -1
c= 10
Step-by-step explanation:
First we start by multiplying both sides of 1/2c = 5 by 2.
c = 10
Add b to both sides of the last equation to make it a=b+5
knowing these two things, we can plug them into the first equation like this:
2(b+5) + b + 10 = 17
then you solve for b:
distribute the 2
2b + 10 + b + 10 = 17
combine like terms
3b + 20 = 17
subtract 20 from each side
3b = -3
divide by 3
b = -1
then you can plug that into the last equation again so a - (-1) =5
Subtracting a negative is the same as adding so its a + 1 = 5 or a = 4
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For a system of linear equations to have no solution, they must be parallel. If you imagine the graph of two parallel lines, they can never intersect, meaning there cannot be a solution/a point that is on both lines.
For two lines to be parallel they must have the same slope, so the m value of both equations are the same. The b value can be any value you want, as long as they don't have the same b value (or else they'd be the same line! and the same lines have an infinite number of solutions).
One pair could be:
y=3x+3 and y=3x+9
But you can come up one yourself you'd like :)
<span> -63 + w = 55
Add 63 to both sides
Final Answer: w = 118</span>