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4 years ago

5 divide 3/4 in simplest

Mathematics

1 answer:

xenn [34]4 years ago

6 0

Answer:

20/3

Step-by-step explanation:

5/(3/4)=(5/1)(4/3)=20/3

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At what rate of interest whould rs 1800 amount to 2500 in 2 years

Trava [24]

A = P(1+r)^t
A = amount made after the specified time
P = original amount of money
r = rate
t = time

2500 = 1800 (1 + r)^2
2500/1800=(1800(1+r)^2)/1800
1.3888 = (1+r)^2
1.17851 = (1 +r)
1.17851 - 1 = r
Rate = .17851

7 0

3 years ago

Vijay is building a new rectangular enclosure in his backyard for his chickens. He has 40 feet of fencing material and he wants

Sloan [31]

The answer is C

The reason: There are two width and two length sides. So, therefore, if you want the fencing to equal 40 feet around the perimeter, 8 · 2 + L · 2 has to = 40.
You would factor 2 out, and you get 2(8 + L) = 40.

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3 years ago

You roll a number cube twice. Find the probability of the events. Rolling an even number of 5.

lys-0071 [83]

Answer:

An even number and a 5. In the first roll you can get 2, 4 or 6, so you have 3 out of 6 options, the probability is 3/6 = 1/2, in the second roll you need you get a 5, the probability is 1/6.

I really hope this helps please give brainliest!!!!

5 0

3 years ago

Solve the following questions <br> 1/6x + 2/3=1/4x-1/3

VladimirAG [237]

I hope it helps you ❤️❤️❤️

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3 years ago

Read 2 more answers

A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate

liraira [26]

Answer:

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}$

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle $(r_{1})$ = 9 inches

Area of first circle = $\pi r_{1} ^{2}$

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = $9 \times \frac{2}{3} = 6\ inches$

Area of second circle = $\pi r_{2} ^{2}$

Area of second circle = 6 × 6 × π = 36 π

Now,

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }$

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}$

∵ $(r_{1})$ = 9 inches and $(r_{2})$ = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., $\frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}$

8 0

3 years ago