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8_murik_8 [283]
3 years ago
8

Which is not an advantage that a reflector telescope has over a refractor telescope? A. Flaws and bubbles in the material inside

a thick mirror are not a problem, while flaws and bubbles in the material inside a thick lens are. B. Reflectors can be built with much bigger apertures. C. The device that collects the light is more easily supported in a reflector. D. Reflectors avoid the problem of chromatic aberration in the lens. E. A reflector doesn’t have to deal with the twinkling of the stars, as a refractor does.
Physics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

Answer E is false because the two instruments see the flickering of the stars, so this is not a characteristic of a reflector

Explanation:

Let's analyze the characteristics of a reflecting telescope.

 

- use reflection to create images

- does not have the chromatic aberration problem

Let's see the responses a, b, c and d are characteristics of a refractor

Answestars, so this is not a characteristic of a reflector

Answer E is false because the two instruments see the flickering of the stars, so this is not a characteristic of a reflector

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Which object represents a negatively charged particle? which object represents a positively charged molecule? which object repre
kari74 [83]

The answers to your questions are as written below:

  • The objects that represents a negatively charged particle is : Image B
  • The object that represents a positively charged molecule is : Image A
  • The object that represents an uncharged molecule is : Image C
  • The object the will not move when in an electric fied is : Image C

<h3>Different types of charges molecules</h3>

A negatively charged molecule move inwards when placed in an electric field while positively charged molecule placed in a electric field will move outwards the electric field.

A neutral/uncharged molecule will remains still when placd in an elctric field due to the absence of charges.

Hence we can concude that the answers to your questions are as listed above.

Learn more about electric charges :brainly.com/question/857179

#SPJ4

attached below is the missing image

8 0
2 years ago
Two mirrors are set up at an angle of 90.0°. If light is incident on the first mirror at an angle of 34.6° from the normal, at w
oksano4ka [1.4K]

Answer:

angle of incidence for the second mirror is 55.4 degree  

Explanation:

Given data;

Angle between two mirror is 90 degree

Incident angle on first mirror is 34.6 degree

For first mirror

Angle of incidence  is equal to  angle of reflection

34.6 degree = angle of reflection

r_1 = 42.5 degree

Now , for the triangle ABC         [from figure]

90 - r_1 + 90 + 90 - i_1 = 180

34.6 + i_1 = 90

i_1 = 55.4 degree

The angle of incidence for

angle of incidence for the second mirror is 55.4 degree  

4 0
3 years ago
A typical person's eye is 2.5 cm in diameter and has a near point (the closest an object can be and still be seen in focus) of 2
Paraphin [41]

Answer:

2.27 cm

2.5 cm

Explanation:

u = Object distance =  25 cm

v = Image distance = 2.5 cm

f = Focal length

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{25}+\frac{1}{2.5}\\\Rightarrow \frac{1}{f}=\frac{11}{25}\\\Rightarrow f=\frac{25}{11}=2.27\ cm

The minimum effective focal length of the focusing mechanism of the typical eye is 2.27 cm

when u=\infty

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{\infty}+\frac{1}{2.5}\\\Rightarrow \frac{1}{f}=\frac{1}{2.5}\\\Rightarrow f=\frac{2.5}{1}=2.5\ cm

The maximum effective focal length of the focusing mechanism of the typical eye is 2.5 cm

3 0
3 years ago
a student determines the circumference of a golf ball. a man pulls a sledge of mass 25 kg across level ground with a horizontal
Travka [436]

Explanation:

Fnet = Ft - Ff = 60N - 20N = 40N

a = Fnet / m = 40N / 25kg = 1.6m/s².

4 0
3 years ago
Read 2 more answers
Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja
igor_vitrenko [27]

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

<u>a = 3.33 m/s²</u>

8 0
3 years ago
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