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Evgen [1.6K]
3 years ago
10

a student determines the circumference of a golf ball. a man pulls a sledge of mass 25 kg across level ground with a horizontal

force of 60 N. a constant force of friction of 20 N acts on sledge. what is the acceleration of the sledge?​
Physics
2 answers:
Travka [436]3 years ago
4 0

Explanation:

Fnet = Ft - Ff = 60N - 20N = 40N

a = Fnet / m = 40N / 25kg = 1.6m/s².

tatiyna3 years ago
4 0

Calculate resultant force:

R = ma

Descomposing:

F - Fr = ma

Replacing we have:

60 N - 20 N = 25 kg * a

Resolving:

40 N = 25 kg * a

40 N / 25 kg = a

1,6 m/s^2 = a

The aceleration is <u>1,6 meters per second squared.</u>

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A wheel free to rotate about its axis that is not frictionless is initially at rest. A constant external torque of +46 N·m is ap
Rom4ik [11]

Answer:

Explanation:

Let Torque due to friction be

F  

Net torque

= 46 - F

Angular impulse = change in angular momentum

=(  46 - F ) x 17  = I X 580

When external torque is removed , only friction creates torque reducing its speed to zero in 120 s so

Angular impulse = change in angular momentum

F  x 120 = I X 580

(  46 - F ) x 17 = F  x 120

137 F = 46 x 17

F = 5.7 Nm

b )

Putting this value in first equation

5.7 x 120 = I x 580

I = 1.18 kg m²

8 0
3 years ago
What did nicolaus copernicus discover about the universe
Keith_Richards [23]

Answer:

Copernicus discoveres thr heliocentric theory. It was previously believed that everything orbited the Earth, geocentric theory. Copernicus said he believed the Earth and everything else orbited around the Sun.

8 0
3 years ago
A sphere of radius R has total charge Q. The volume charge density (C/m3) within the sphere is rho(r)=C/r2, where C is a constan
san4es73 [151]

Answer: C = Q/4πR

Explanation:

Volume(V) of a sphere = 4πr^3

Charge within a small volume 'dV' is given by:

dq = ρ(r)dV

ρ(r) = C/r^2

Volume(V) of a sphere = 4/3(πr^3)

dV/dr = (4/3)×3πr^2

dV = 4πr^2dr

Therefore,

dq = ρ(r)dV ; dq =ρ(r)4πr^2dr

dq = C/r^2[4πr^2dr]

dq = 4Cπdr

FOR TOTAL CHANGE 'Q', we integrate dq

∫dq = ∫4Cπdr at r = R and r = 0

∫4Cπdr = 4Cπr

Q = 4Cπ(R - 0)

Q = 4CπR - 0

Q = 4CπR

C = Q/4πR

The value of C in terms of Q and R is [Q/4πR]

7 0
3 years ago
A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.
marin [14]
Calculate the circumference of the circular path of the wheel by the equation,
    C = 2πr
where C is the circumference,
           r is the radius

Substituting the known values,
    C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,
 
     T = (3.06 m) / (5.75 /s) = 0.53 s

<em>ANSWER: 0.53 s</em>
3 0
3 years ago
A chemical change can be represented by ____________ changing into _____________ in a ________________.
Harrizon [31]

Answer:

I don't know but I explain some of it as best as I can

Explanation:

Substances that start a chemical reaction are called reactants. Substances that are produced in the reaction are called products. Reactants and products can be elements or compounds. Bonds break in the reactants and new bonds form in the products.

3 0
3 years ago
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