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Pani-rosa [81]
3 years ago
6

Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja

. If Derek pulls horizontally on the dog with a force of 10.0 N and Anudja pulls with a horizontal force of 11.0 N, what is the horizontal acceleration of the dog?
Physics
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

<u>a = 3.33 m/s²</u>

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Answer:

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Forward direction will be positive while backward direction will be negative

Total displacement = +10 - 20 + 40

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Anon25 [30]
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