I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B
Answer: Accelaration is 2.77 m/s*s
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Explanation:
V0=0km/h=0m/s
V1=100 km/h=27.7 m/s
t=10s=
Use equation for accelaration : a=(V1-V0)/t
a=(0m/s-27.7m/s)/10s
a=-27.7s/10s
a=2.77m/s*s
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
Answer:
Explanation:
Given that,
A sphere has a volume of V and a radius r
Volume of sphere cam be determine using the formula
V = 4/3 πr³
V = 4πr³ / 3.
If the radius of the sphere is increasing by
dr / dt = 5cm / min
How fast is the volume increasing when r = 10cm
dV / dt =?
From V = 4πr³ / 3
We can calculate dV/dr
dV/dr = 12πr² / 3
dV/dr = 4πr²
Then,
We want to find dV/dt
Using chain rule
dV/dt = dV/dr × dr / dt
dV/dt = 4πr² × 5
dV/dt = 20πr²
So, at r = 10
dV/dt { 20π × 10²
dV/dt = 6283.19 cm/min
The rate at which the volume increase is 6283.19 cm/min
First we need to know the equation which is P=mv
Use the formula- 3.2 kg x m/s = 762 x V
divide 762 in both side to get the v by itself
now we will have 0.004193971166 and lets round it!
then we will have the answer of .0042
