I think that u need to use the book because it said which part from number 3? not sure tho<span />
I believe the answer would be B I think sorry in advance if im incorrect
I almost wanna say the orange red green blue thing because that's what it looks like but maybe you'll get an answer from this
Answer:
The frequency of A1 be on Big Pine Key after a single generation of migration from No Name Keyp is 0.2276
Explanation:
Whenever it occurs migration between two populations, there is genetic flux going on. Genetic flux might be considered as an evolutive strength only if migration > 0 and if the allelic frequency in one generation is different from the allelic frequency in the next generation.
Genetic flux acts homogenizing the allelic frequencies between the two populations, and it might introduce variability.
By knowing the allelic frequencies in both populations at a certain time and the migration rate, we can calculate the allelic frequencies of populations in the next generation. This is:
pA₂=pA₁(1-m)+pB₁ m
pB₂=pB₁(1-m)+pA₁ m
Being
- A one population and B the other population
- pA₁ and pB₁ the frequencies of the p allele before migration,
- pA₂and pB₂ the frequencies of the p allele after migration,
- m the migration rate
In the exposed example, we know that:
- No Name Key population allelic frequency: A1 = 0.43 and A2 = 0.57
- Big Pine Key population allelic frequency: A1 =0.21 and A2 = 0.79
Let´s say that p represents A1 allele, and q represents A2 allele.
The frequency of A1 allele (p) be on Big Pine Key (Population B) after a single generation of migration from No Name Key (Population A)
pB₂=pB₁(1-m)+pA₁ m
pB₂=0.21 x (1 - 0.08) + 0.43 x 0.08
pB₂= 0.2276
The allelic frequency in a population after one generation is the allelic frequency of individuals of that population that did not migrate (21 x (1 - 0.08) plus the allelic frequency of the new individuals that came from the other population (0.43 x 0.08).
You can corroborate your result by calculating the q allele frequency in the next generation and summing both of them up. The result should be one.
qB₂= qB₁(1-m)+qA₁ m
qB₂= 0.79 x (1 - 0.08) + 0.57 x 0.08
qB₂= 0.7724
p + q = 1
0.2276 + 0.7724 = 1
